7:
\(\Leftrightarrow\left(x-3\right)\left(x-1\right)=2\left(x-1\right)+\left(x-5\right)\left(x-3\right)\)
\(\Leftrightarrow x^2-4x+3=2x-2+x^2-8x+15\)
=>-4x+3=-6x+13
=>2x=10
hay x=5(nhận)
5: \(\Leftrightarrow\left(2x+5\right)\left(x+5\right)-2x^2=0\)
=>2x2+10x+5x+25-2x2=0
=>15x=-25
hay x=-5/3
10: \(\Leftrightarrow\left(2x-5\right)\left(x-1\right)-2x\left(x+3\right)=4\)
\(\Leftrightarrow2x^2-2x-5x+5-2x^2-6x=4\)
=>-13x=-1
hay x=1/13
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