Question

Answer 1

c, \(6x-6-4x+8=12x-3x+9\Leftrightarrow2x+2=9x+9\)

\(\Leftrightarrow7x=-7\Leftrightarrow x=-1\)

Answer 2

\(\dfrac{x-1}{2}-\dfrac{x-2}{3}=x-\dfrac{x-3}{4}\)

\(\Leftrightarrow\dfrac{6x-6}{12}-\dfrac{4x-8}{12}=\dfrac{12x}{12}-\dfrac{3x-9}{4}\)

\(\Rightarrow6x-6-4x+8=12x-3x+9\)

\(\Leftrightarrow-7x=7\)

\(\Leftrightarrow x=-1\)