Question

Answer 1

\(n_{Ba(HCO_3)_2} = 0,5.0,6 = 0,3(mol)\)

Ba(HCO₃)₂ + NaOH→ NaHCO₃ + BaCO₃ + H₂O

x........................x................................x...................................(mol)

Ba(HCO₃)₂ \(\xrightarrow{t^o}\) BaCO₃ + CO₂ + H₂O

x...........................x................................................(mol)

Suy ra: x + x = 0,3 ⇒ x = 0,15

\(\Rightarrow C_{M_{NaOH}} = \dfrac{0,15}{0,2}=0,75M\)

Đáp án D