\(a,Zn+2HCl\rightarrow ZnCl_2+H_2\\ n_{H_2}=n_{Zn}=n_{ZnCl_2}=\dfrac{4,48}{22,4}=0,2\left(mol\right)\\ m_{Zn}=0,2.65=13\left(g\right)\\ m_{ZnO}=21,1-13=8,1\left(g\right)\\ n_{ZnO}=\dfrac{8,1}{81}=0,1\left(mol\right)\\ ZnO+2HCl\rightarrow ZnCl_2+H_2O\\ b,\%m_{Zn}=\dfrac{13}{21,1}.100\approx61,611\%\\ \%m_{ZnO}\approx38.389\%\\ c,n_{ZnCl_2}=n_{Zn}+n_{ZnO}=0,2+0,1=0,3\left(mol\right)\\ m_{muoi}=m_{ZnCl_2}=127.0,3=38,1\left(g\right)\)
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