Bài 5:
a) Ta có: \(\left\{{}\begin{matrix}p+e+n=93\\p=e\\n-p=6\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3p=87\\n-p=6\\p=e\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}p=e=29\\n=35\end{matrix}\right.\)
\(\Rightarrow A=p+n=29+35=64\left(u\right)\)
\(KHNT:^{64}_{29}Cu\)
b) Ta có: \(\left\{{}\begin{matrix}p+e+n=48\\p=e\\p+e=2n\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}3n=48\\p=e=n\end{matrix}\right.\Leftrightarrow p=e=n=16\)
\(\Rightarrow A=p+n=16+16=32\left(u\right)\)
\(KHNT:^{32}_{16}S\)
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