Qua O kẻ Om//a
\(\Rightarrow\widehat{A_1}=\widehat{O_1}=30^0\) (so le trong)
a//b, Om//a ⇒Om//b
\(\widehat{O_2}=\widehat{B_1}=45^0\) (so le trong)
Ta có: \(\widehat{O_1}+\widehat{O_2}=\widehat{AOB}\)
\(30^0+45^0=\widehat{AOB}\)
\(\Rightarrow\widehat{AOB}=75^0\)