Lời giải:
a.
\(\frac{3}{7}=\frac{3\times 11}{7\times 11}=\frac{33}{77}\)
b.
\(\frac{22}{11}=\frac{2\times 11}{11}=2=\frac{10}{5}< \frac{11}{5}\)
c.
\(\frac{7}{2}=\frac{7\times 4}{2\times 4}=\frac{28}{8}> \frac{13}{8}\)
d.
\(\frac{2007}{2006}>1\) do $2007> 2006$
$\frac{2006}{2008}< 1$ do $2006< 2008$
Suy ra $\frac{2007}{2006}> \frac{2006}{2008}$
a: \(\dfrac{3}{7}=\dfrac{3\cdot11}{7\cdot11}=\dfrac{33}{77}\)
b: \(\dfrac{22}{11}=2\)
\(\dfrac{11}{5}>2\)
Do đó: \(\dfrac{22}{11}< \dfrac{11}{5}\)
c: \(\dfrac{7}{2}=\dfrac{7\cdot4}{2\cdot4}=\dfrac{28}{8}>\dfrac{13}{8}\)