(1+100)x100:2=5050

a>b 1 đơn vị 

Theo đầu bài ta có:
\(\frac{x-a}{b}+\frac{x-b}{a}=\frac{b}{x-a}+\frac{a}{x-b}\)
\(\Rightarrow\frac{a\left(x-a\right)+b\left(x-b\right)}{ab}=\frac{b\left(x-b\right)+a\left(x-a\right)}{\left(x-a\right)\left(x-b\right)}\)
\(\Rightarrow ab=\left(x^2-xb\right)-\left(xa-ab\right)\)
\(\Rightarrow x\left(x-b-a\right)=0\)
\(\Rightarrow\hept{\begin{cases}x=0\\x-\left(a+b\right)=0\end{cases}}\Rightarrow\hept{\begin{cases}x=0\\x=a+b\end{cases}}\)

5 + 2 +2 +3 +5 = 10 + 4 + 3 = 10 + 7 = 17

5 + 3 +4 +6 +7 = 8 + 10 + 7 = 10 + 15 = 25 

5 + 5 + 5 + 5 + 5=5 x 5 = 25