HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
a) ta có: \(32^{10}\)=\(\left(2^5\right)^{10}\)= \(2^{50}\)
\(8^{13}\)= \(\left(2^3\right)^{13}\)= \(2^{39}\)
=> \(2^{50}>2^{39}\)=>\(32^{10}>8^{13}\)
b) ta có: \(9^5=\left(3^2\right)^5=3^{10}\)
\(32^2=\left(2^5\right)^2=2^{10}\)
=> \(3^{10}< 2^{10}\)=> \(9^5< 32^2\)
c, ta có \(16^{19}=\left(2^4\right)^{19}=2^{76}\)
\(8^{25}\)\(=\left(2^3\right)^{25}=2^{75}\)
=> \(2^{76}>2^{75}\)=> \(6^{19}>8^{25}\)
d, \(27^{11}=\left(3^3\right)^{11}=3^{33}\)
\(81^8=\left(3^4\right)^8=3^{32}\)
=> \(3^{33}>3^{32}\)=>
A={0+2+4+6+8+10+.......+100}
B={1+3+5+7+9+........+99}
A - B={0+2+4+6+8+10+.....+100} - {1+3+5+7+9+.......+99}
= 2601- 2500=101
a)XXVI: hai muơi sáu
XXIX: hai mươi chín
b) 15: XV
28: XXVIII
c) IV=V-I