do metan k tác dụng với đ br

%\(VCH_4\)=\(\frac{1,12}{2,24}\times100\)=50%

%vC2H4=100-50=50%

nC2H4=\(\frac{2,24-1,12}{22,4}\)=0,05

pthh:

C2H4 +br2 \(\rightarrow\)C2H4Br2

\(\Rightarrow\)nBr2=0,05

mBr2=0,05\(\times\)160=8(g)

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