ta có \(=\frac{3n+8}{n+1}\left(n\ne-1\right)\)

        \(=\frac{3n+3+5}{n+1}\left(n\ne-1\right)\)

         \(=\frac{3\left(n+1\right)+5}{n+1}\left(n\ne-1\right)\)

         \(\Rightarrow n+1\inƯ\left(5\right)=\left\{1;5\right\}\)

         Nếu n+1=1=>n=0

          Nếu n+1=5=>n=4

         Vậy n=0;4

1 . D

2 . D

3 . A

4 . D

hi Tran Thi Thu Huong

I am not bad

I am very very cold