HOC24
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Chủ đề / Chương
Bài học
Giải các phương trình sau:
g/ x(x + 3)(x – 3) – (x + 2)(x2 – 2x + 4) = 0h/ (3x – 1)(x2 + 2) = (3x – 1)(7x – 10)i/ (x + 2)(3 – 4x) = x2 + 4x + 4k/ x(2x – 7) – 4x + 14 = 0m/ x2 + 6x – 16 = 0n/ 2x2 + 5x – 3 = 0
\(h.\dfrac{3\left(2x-1\right)}{4}-\dfrac{3x+1}{10}+1=\dfrac{2\left(3x+2\right)}{5}\)
\(i.\dfrac{\left(2x+1\right)^2}{5}-\dfrac{\left(x-1\right)^2}{3}=\dfrac{7x^2-14x-5}{15}\)
\(k.x+\dfrac{2x+\dfrac{x-1}{5}}{3}=1-\dfrac{3x-\dfrac{1-2x}{3}}{5}\)
\(g.\dfrac{5\left(x-1\right)+2}{6}-\dfrac{7x-1}{4}=\dfrac{2\left(2x+1\right)}{7}-5\)
a/ (3x – 2)(4x + 5) = 0b/ (2,3x – 6,9)(0,1x + 2) = 0c/ (4x + 2)(x2 + 1) = 0d/(2x + 7)(x – 5)(5x + 1) = 0e/ (x – 1)(2x + 7)(x2 + 2) = 0f/ (3x + 2)(x2 – 1) = (9x2 – 4)(x + 1)