Câu trả lời:
|x+1| - \(\dfrac{2}{3}\)= 1\(\dfrac{3}{5}\)
|x+1| = 1\(\dfrac{3}{5}\) + \(\dfrac{2}{3}\)
|x+1| = \(\dfrac{34}{15}\)
⇒ x+1 = \(\dfrac{34}{15}\) hoặc x+1 = \(\dfrac{-34}{15}\)
⇒ x = \(\dfrac{34}{15}\) - 1 hoặc x = \(\dfrac{-34}{15}\) - 1
⇒ x = \(\dfrac{19}{15}\) hoặc x = \(\dfrac{-49}{15}\)
