Câu c bạn tính sai r nhé

c, \(\dfrac{8}{5}\cdot\dfrac{6}{19}+\dfrac{13}{19}\cdot\dfrac{16}{10}+\dfrac{2}{5}=\dfrac{8}{5}\cdot\dfrac{6}{19}+\dfrac{13}{19}\cdot\dfrac{8}{5}+\dfrac{2}{5}\)

\(=\dfrac{8}{5}\cdot\left(\dfrac{6}{19}+\dfrac{13}{19}\right)+\dfrac{2}{5}=\dfrac{8}{5}\cdot1+\dfrac{2}{5}=\dfrac{8}{5}+\dfrac{2}{5}=\dfrac{10}{5}=2\)

d. \(\dfrac{2^3\cdot4\cdot2^4}{8\cdot2^5}=\dfrac{2^3\cdot2^2\cdot2^4}{2^3\cdot2^5}=\dfrac{2^{3+2+4}}{2^{3+5}}=\dfrac{2^9}{2^8}=2\)

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