HOC24
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Môn học
Chủ đề / Chương
Bài học
Rút gọn
A=\(\left(\dfrac{1}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{x-9}\right)\dfrac{2\sqrt{x}}{\sqrt{x}-1}\)
B=\(\left(\dfrac{3}{\sqrt{x-1}}+\sqrt{1-x}\right):\left(\dfrac{3}{\sqrt{1-x^{ }}^2}+1\right)\)
A=\(\left(\dfrac{4x}{\sqrt{x}-1}-\dfrac{\sqrt{x}-2}{x-3\sqrt{x}+2}\right)\dfrac{\sqrt{x}-1}{x^2}\)
B=\(\left(\dfrac{\sqrt{x}}{3+\sqrt{x}}+\dfrac{9+x}{9-x}\right)\left(3\sqrt{x}-x\right)\)
A=\(\left(\dfrac{1}{\sqrt{a}+2}+\dfrac{1}{\sqrt{a}-2}\right):\dfrac{\sqrt{a}}{a-4}\)
B=\(\left(\dfrac{5\sqrt{x}-6}{x-9}+\dfrac{2}{\sqrt{x+3}}\right):\left(1+\dfrac{6}{x-9}\right)\)
Tìm x
\(\sqrt{3x-6}-x=-2\)
A=\(\dfrac{a^2-9}{12}:\sqrt{\dfrac{a^2+6a+9}{16}}với\) a<-3