Cho bthuc A=\(\dfrac{2}{x+\sqrt{x}+1}\)

Tìm x để A>0

Cho bthuc : A=\(\dfrac{2\sqrt{x}}{x-2}\)

Tìm x để A<0

 Lan said “ I’m sorry , I can’t do this exercise “ =>Lan said that……………………………………………………………………………………….

Cho bthuc 

A=\(\left(\dfrac{x+2}{x\sqrt{x}-1}+\dfrac{\sqrt{x}}{x+\sqrt{x}+1}+\dfrac{1}{1-\sqrt{x}}\right):\dfrac{\sqrt{x}-1}{2}\) với \(x\ge0,x\ne1\)

a,Rút gọn A

b,Chứng minh C>0

Cho bthuc

A=\(\left(\dfrac{\sqrt{x}+3}{1-x}-\dfrac{3}{1-\sqrt{x}}\right):\left(1-\dfrac{1}{x-1}\right)\) với \(x\ge0,x\ne1\)

a,Rút gọn A

b,Tính B khi x=\(7+4\sqrt{3}\)

c,Tìm x đê B<0

Cho bthuc

A=\(\dfrac{2\sqrt{x}-9}{x-5\sqrt{x}+6}-\dfrac{\sqrt{x}+3}{\sqrt{x}-2}-\dfrac{2\sqrt{x}+1}{3-\sqrt{x}}\) 

a,Tìm ĐKXĐ

b,Rút gọn A

Cho bthuc

A=\(\left(\dfrac{x+2}{x\sqrt{x}+1}+\dfrac{\sqrt{x}}{x+\sqrt{x}+1}+\dfrac{1}{1-\sqrt{x}}\right):\dfrac{\sqrt{x}-1}{2}\) với \(x\ge0,x\ne1\)

a, Rút gọn A

b, Chứng Minh A>0