Câu trả lời:

\(\sqrt{3}\cdot x+\sqrt{3}=\sqrt{12}+\sqrt{27}\)

\(\Leftrightarrow\sqrt{3}\left(x+1\right)=2\sqrt{3}+3\sqrt{3}\)

\(\Leftrightarrow\sqrt{3}\left(x+1\right)=\sqrt{3}\left(2+3\right)\)

\(x+1=5\)

\(x=4\)