2ch 2con

Ta có:

\(\left(x-8\right)^2=225\)Vì \(225=15^2;225=\left(-15\right)^2\)

\(TH_1:x-8=15\)\(\Rightarrow x=15-8\Rightarrow x=7\)

\(TH_2:x-8=-15\)\(\Rightarrow x=-15-8\Rightarrow x=-23\)

Vậy \(x\in\left\{7;-23\right\}\)