HOC24
Lớp học
Môn học
Chủ đề / Chương
Bài học
a. Ta có :
x2-9= (x-3)(x+3)
=> Mtc : (x-3)(x+3)
Nhân tử phụ 1 : (x-3)(x+3):(x-3)(x+3)=1
Nhân tử phụ 2 : (x-3)(x+3):(x+3)=x-3
Qui đồng:
x+15/x2-9= x+15/(x-3)(x+3)=(x-15).1/(x-3)(x+3).1=x-15/(x-3)(x+3)
2/x+3=2.(x-3)/(x+3)(x-3)=2(x-3)/(x-3)(x+3)
x-15/(x-3)(x+3) + 2(x-3)/(x-3)(x+3)
= (x-15)+2(x-3)/(x-3)(x+3)
= x-15+2/x+3
= x-13/x+3
b . n=36x1023/6x1023=6(mol)
V=6x22,4=134,4 g
a . mA= 0,5x32=16 g
5C
1B
1. Jim will pick me to the airport tomorrow
=> i will picked to the airport by Jim tomorrow
2. Peter wrote his report last week
=> his report was written by peter last week
3. They will replace the old equipment with new one
=> The old equipment will replaced with new one
a. nMg=4.8/24=0,2(mol)
nCao=5.6/56=0,1(mol)
nCa=7.4/74=0,1(mol)
b. nC02= 4.48/22.4=0,2(mol)
2 b
1 B
c.nSO2=4,48:22,4=0,2
mSO2= 0,2x64=12,8 g
d.nH2=11,2:22,4=0,5 mol
mH2=0,5x2=1g
nO2=5,6:22,4=0,25 mol
mO2=0,25x32=8g