\(3,2m^3=3200dm^3\)

\(45,67dm^3=45670cm^3\)

\(9m^345dm^3=9,045m^3\)

\(6dm^3852cm^3=6852cm^3\)

1A

2D

\(\left(75\%+\dfrac{7}{3}\right):\left(\dfrac{2}{9}-2\dfrac{5}{2}\right)\)

\(=\left(\dfrac{3}{4}+\dfrac{7}{3}\right):\left(\dfrac{2}{9}-\dfrac{9}{2}\right)\)

\(=\left(\dfrac{9}{12}+\dfrac{28}{12}\right):\left(\dfrac{4}{18}-\dfrac{81}{18}\right)\)

\(=\dfrac{37}{12}:\dfrac{-77}{18}\)

\(=-\dfrac{111}{154}\)

Vì 2 số lẻ cách nhau 2 đơn vị nên hiệu giữa chúng là 2

Số lớn là : (2004+2):2=1003

Số bé là : 2004-1003=1001

ĐS....

\(16x^2-9=\left(4x-3\right)\left(4x+3\right)\)

\(16x^2-8x+1=\left(4x-1\right)^2\)

\(\dfrac{1919}{2323}\times\dfrac{464646}{747474}\times\dfrac{37}{19}\)

\(=\)\(\dfrac{1919:101}{2323:101}\times\dfrac{464646:10101}{747474:10101}\times\dfrac{37}{19}\)

\(=\dfrac{19}{23}\times\dfrac{46}{74}\times\dfrac{37}{19}\)

\(=\dfrac{19\times23\times2\times37}{23\times2\times37\times19}=1\)

\(x+\left(x-1\right)+\left(x-2\right)+...+\left(x-101\right)=-516\)

\(x+x-1+x-2+...+x-101=-516\)

\(\left(x+x+...+x\right)-\left(1+2+...+101\right)=-516\)

\(102x-\left[\left(101+1\right)101:2\right]=-516\)

\(102x-5151=-516\)

\(102x=4635\)

\(x=\dfrac{1545}{34}\)

\(\left(x-3\right)^2+6-2x\)

\(=\left(x-3\right)^2-2\left(x-3\right)\)

\(=\left(x-3-2\right)\left(x-3\right)\)

\(=\left(x-5\right)\left(x-3\right)\)

\(\dfrac{x-1}{2}-\dfrac{7x+3}{15}\le\dfrac{2x+1}{3}+\dfrac{3-2x}{5}\)

\(\Leftrightarrow\dfrac{15\left(x-1\right)}{30}-\dfrac{2\left(7x+3\right)}{30}\le\dfrac{10\left(2x+1\right)}{30}+\dfrac{6\left(3-2x\right)}{30}\)

\(\Leftrightarrow15x-15-14x-6\le20x+10+18-12x\)

\(\Leftrightarrow x-21\le8x+28\)

\(\Leftrightarrow x-8x\le28+21\)

\(\Leftrightarrow-7x\le49\)

\(\Leftrightarrow x\ge-7\)

Vậy...

\(C=4\left(x-1\right)+2x\left(xy^2-y\right)+y\left(x^2-x\right)-x\left(xy+3\right)\)

    \(=4x-4+2x^2y^2-2xy+x^2y-xy-x^2y-3x\)

    \(=2x^2y^2-3xy+x-4\)

Bậc của đa thức C là : 4