A=(x+1)(y² - 6) = 0

Ta có:

\(\left[{}\begin{matrix}\left(x+1\right)=0\\\left(y^2-6\right)=0\end{matrix}\right.\left[{}\begin{matrix}x=\left(-1\right)\\y^2=6\Rightarrow y=\sqrt{6}\end{matrix}\right.\)

Vậy x = (-1) ; y = \(\sqrt{6}\)

- Coi vậy đúng chưa nhé bạn!