Câu trả lời:
Vì \(\frac{x}{3}=\frac{y}{4}=>x=\frac{3}{4}y\)
\(\frac{y}{5}=\frac{z}{6}=>z=\frac{6}{5}y\)
Ta có
\(M=\frac{2x+3y+4z}{3x+4y+5z}=\frac{2.\frac{3}{4}y+3y+4.\frac{6}{5}y}{3.\frac{3}{4}y+4y+5.\frac{6}{5}y}=\frac{\frac{93}{10}y}{\frac{49}{4}y}=\frac{93}{10}:\frac{49}{4}=\frac{186}{245}\)