ADCT:C%1×md1=C%2×md2

→C%1=C%2*md2/md1=79,35%

a/Na2O+H2O---->2HNO3

c/H2O+K2O----->2KOH

d/Fe2O3+6HCl----->2FeCl3+3H2O

e/2Al+3CuO------>Al2O3+3Cu

+HNO3:hidronitorat

+Al2(SO4):nhôm(II)sunfat

+KOH:kalihidroxit

+FeCl3:sắt(II)clorua

+Al2O3:nhôm(III)oxit

+CaO+H2O----->Ca(OH)2

+2Al+3H2SO4----->Al2(SO4)3+3

H2

ADCT:mddHCl=16,12×100÷10=161,2(g)

k lượng HCl cần dùng là 161,2 gam

+KClO3--->2KCl+3O2

+3Fe+2O2--->Fe3O4

+Fe3O4+4H2--->Fe3+4H2O

+Fe+H2SO4--->FeSO4+H2

+2H2+O2--->2H2O