HOC24
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Môn học
Chủ đề / Chương
Bài học
e) TH1: x-1>0 => x>1<=> (x+1)^2 + x-1= x^2 +4<=> x^2 +2x +1 +x-1=x^2 +4<=>x=4/3(t/m)TH2: x-1<0 => x<1<=> (x+1)^2 -x+1= x^2 +4<=> x^2 +2x+1-x+1=x^2 +4<=> x=2(loại)
bài 2d) TH1: x+2>0 => x>-2<=> x+2=3x+4<=> x=-1(t/m)TH2: x+2<0 => x<-2<=> -x-2=3x+4<=> x=-3/2(loại)
a) <=> 11x-5x<4+20<=> x<4b) <=> x^2 -9<x^2 +4x+4+3<=> x^2-x^2-4x<4+3+9<=> x>-4c) \(\Leftrightarrow\dfrac{6\left(2x+1\right)}{12}+\dfrac{36}{12}\ge\dfrac{4\left(3x-5\right)}{12}-\dfrac{3\left(4x+1\right)}{12}\)<=> 12x+6+36\(\ge\)12x-20-12x-3<=> 12x-12x+12x\(\ge\)-20-3-6-36<=> x\(\ge\)\(-\dfrac{65}{12}\)
Tham khảo:
bài 5a) 2^n . 4 = 128=> 2^n=32=> 2^n=2^5=> n=5b) (2n+1)^3=125=> (2n+1)^3=5^3=> 2n+1=5=> 2n=4=> n=2
bài 4a) 3^3 . 27 : 81=27.27:81=729:81=9b)100.1000.10000-10^9=10^9-10^9=0
f) \(=x^2+2x-7x-14=x\left(x+2\right)-7\left(x+2\right)=\left(x-7\right)\left(x+2\right)\)