\(\dfrac{15^3+5.15^2-5^3}{18^3+6.18^2-6^3}\)

12+8.(\(\dfrac{-1}{2}\))\(^3\)+\([\left(2023\right)^0:\dfrac{1}{2}]^2\)

there are some books on the tables

korea foods is different from america foods

my grandpa plays chess with me in the evening

\(\dfrac{5^{x+1}}{125}\)=\(\dfrac{1}{25^{x-2}}\)

\(\dfrac{\left|3x-1\right|}{3}\)=\(\dfrac{5}{4}\)