tìm x, biết
a/ (3x)2 : 32 = 1/243
b/ ( 3x2 - 51 )2n = ( -24)2n ; (n thuộc N*)
Tìm x biết: (3x2-51)2n=(-24)2n
3x2-51 = 24
=>3x2=75
=>x2=25
=> x = + - 5
(x-2/9)^3=(2/30)^6
(3x^2-51)^2n=(-24)^2n
(8x-1)^2n+1=5^2n+1
(5x+1)2=36/49
(3x-2)5=-243
5x=125
(3x2-51)2n=(-24)2n (n thuoc N*)
(5x+1)2=36/49
(5x+1)2=\(\left(\frac{6}{7}\right)^2\)
5x+1=6/7
5x=-1/7
x=-1/35
5x=125
5x=53
x=3
(3x-2)5=-243
(3x-2)5=(-3)5
3x-2=-3
3x=-1
x=-1/3
tìm x, biết
a/ (3x)2 : 32 = 1/243
b/ ( 3x2 - 51 )2n = ( -24)2n ; (n thuộc N*)
a/ \(\Leftrightarrow3^{2x}:3^2=\left(\frac{1}{3}\right)^5\Rightarrow3^x=\frac{1}{3^5}\Rightarrow3^x.3^5=1\Rightarrow3^{5x}=3^0\)
=> 5x = 0 => x = 0
Tìm x biết: \(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\) (với n thuộc N*)
\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)
\(3x^2-51=-24\)
\(3x^2=27\)
\(x^2=9\)
\(x^2=3^2=\left(-3\right)^2\)
TH1: x=3
TH2: x=-3
=.= hok tốt!!
Tìm x biết
a) x2-2x=-1
b) x3+3x2=-3x-1
a) x2-2x=-1
<=> x2-2x+1=0
<=> (x - 1)2 = 0
=> x = 1
a: Ta có: \(x^2-2x=-1\)
\(\Leftrightarrow x^2-2x+1=0\)
\(\Leftrightarrow\left(x-1\right)^2=0\)
\(\Leftrightarrow x-1=0\)
hay x=1
b: Ta có: \(x^3+3x^2=-3x-1\)
\(\Leftrightarrow x^3+3x^2+3x+1=0\)
\(\Leftrightarrow\left(x+1\right)^3=0\)
\(\Leftrightarrow x+1=0\)
hay x=-1
\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)
\(\left(3x^2-51\right)^{2n}=\left(-24\right)^{2n}\)
\(\Leftrightarrow3x^2-51=-24\)
\(\Leftrightarrow3x^2=27\)
\(\Leftrightarrow x^2=9\)
\(\Leftrightarrow x=\pm3\)
(3x2 - 51)2n = (-24)2n
=> \(\orbr{\begin{cases}3x^2-51=-24\\3x^2-51=24\end{cases}=>\orbr{\begin{cases}3x^2=27\\3x^2=75\end{cases}}}\)
=>\(\orbr{\begin{cases}x^2=9\\x^2=25\end{cases}=>}\orbr{\begin{cases}x=3\\x=5\end{cases}}\)
Giup t bn nữa đi ah.
Tìm n ∈ N, biết:
a) 3n = 243
b) 2n = 256
a) 3n = 35 => n = 5
b) 2n = 28 => n = 8
--thodagbun--
( h tớ lm b đt nè :( )
a) \(3^n=243\)
\(=>3^n=3^5\)
\(=>n=5\)
b) \(2^n=256\)
\(=>2^n=2^8\)
\(=>n=8\)
#Nothings -_-
Hài
a) 3n = 243
=> 3n = 35
=> n = 5
b) 2n = 256
=> 2n = 28
=> n = 8
1, tìm x biết
( 3x^2 - 51)^2n = 576^n
(3x2 - 51)2n = 576n
=> (3x2 - 51)2n = 242n = (-24)2n
\(\Rightarrow\left[\begin{array}{nghiempt}3x^2-51=24\\3x^2-51=-24\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}3x^2=75\\3x^2=27\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}x^2=25\\x^2=9\end{array}\right.\)\(\Rightarrow\left[\begin{array}{nghiempt}\left[\begin{array}{nghiempt}x=5\\x=-5\end{array}\right.\\\left[\begin{array}{nghiempt}x=3\\x=-3\end{array}\right.\end{array}\right.\)
Vậy \(\left[\begin{array}{nghiempt}x=5\\x=-5\\x=3\\x=-3\end{array}\right.\)