( 3x - 2⁴). 7³ = 2.7⁴

3x - 2⁴         = 2.7⁴ : 7³

3x - 16        = 2.7

3x - 16       = 14

3x              = 14 + 16

3x              = 30

x                = 30 : 3

x                = 10

  😅

\(\left(3x-2^4\right).7^5=2.7^6\\ \Rightarrow3x-16=2.7^6:7^5\\ \Rightarrow3x-16=2.7\\ \Rightarrow3x-16=14\\ \Rightarrow3x=30\\ \Rightarrow x=10\)

\(\Leftrightarrow3x-16=2.7^4+7^3=5145\Leftrightarrow3x=5161\Leftrightarrow x=\dfrac{5161}{3}\)

\(\left(3x-2^4\right)-7^3=2.7^4\\ \Leftrightarrow\left(3x-16\right)=2.7^4+7^3\\ \Leftrightarrow3x-16=5145\\ \Leftrightarrow3x=5145+16=5161\\ \Leftrightarrow x=\dfrac{5161}{3}\)

219 - 7(x + 1) = 10²

7(x + 1) = 219 - 10²

7(x + 1) = 219 - 100

7(x + 1) = 119

x + 1 = 119 : 7

x + 1 = 17

x = 17 - 1

x = 16

--------------------

(3x - 2⁴) . 7³ = 2.7⁴

(3x - 16).7³ = 2.7⁴

3x - 16 = 2.7⁴:7³

3x - 16 = 2.7

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

Lời giải:

$10+2x=4^5:4^3=4^2=16$

$2x=16-10=6$

$x=6:2=3$

---------

$2x-6^2:18=3.2^2$
$2x-2=12$

$2x=14$

$x=14:2=7$

--------------

$70-5(x-3)=3.2^5=96$

$5(x-3)=70-3.2^5=-26$

$x-3=\frac{-26}{5}$

$x=3+\frac{-26}{5}=\frac{-11}{5}$

------------------

$19-7(x+1)=10^2=100$

$7(x+1)=19-100=-81$

$x+1=\frac{-81}{7}$

$x=\frac{-81}{7}-1=\frac{-88}{7}$

------------

$(3x-2^4).7^3=2.7^4$

$3x-16=2.7^4:7^3=2.7=14$

$3x=14+16=30$

$x=30:3=10$

=> 3x-2^4 = 2.7

=> 3x - 16 = 14 

=> 3x = 30

=> x = 10

BANG 10 NHE !

( 3x - 2⁴ ) . 7³ = 2.7⁴

=> ( 3x - 16 )  = 2 .( 7⁴ : 7³ )

=> ( 3x - 16 ) = 2 . 7

=> 3x - 16 = 14

=> 3x = 30

=> x = 10

\(\left(3x-2^4\right).7^3=2.7^4\\ \Leftrightarrow3x-16=2.7^4:7^3\\ \Leftrightarrow3x=14+16\\ \Leftrightarrow3x=30\\ \Leftrightarrow x=10\)

Vậy...

\(\left(2x-2^4\right).7^3=2.7^4\)

\(\Leftrightarrow\left(2x-2^4\right)=2.7^4:7^3\)

\(\Leftrightarrow2x-2^4=2.7\)

\(\Leftrightarrow2x-16=14\)

\(\Leftrightarrow2x=30\)

\(\Leftrightarrow x=15\)

Vậy ..

( 3x - 2⁴ ) . 7³ = 2 . 7⁴

( 3x - 16 ) . 343 = 4802

3x - 16 = 4802 : 343

3x - 16 = 14

3x = 14 + 16

3x = 30

x = 30 : 3

x = 10

=>(3x-16)=2*7=14

=>3x=30

=>x=10

\(\left(3x-2^4\right).7^3=2.7^4\)

\(\left(3x-2^4\right)=2.7^4\div7^3\)

\(3x-2^4=2.7\)

\(3x-2^4=14\)

\(3x=14+2^4\)

\(3x=30\)

`=>` \(x=30\div3\)

`=> x=10`

\(\left(3x-2^4\right).7^3=2.7^4\)

=> \(\left(3x-2^4\right)=2.7^4:7^3\)

=> \(\left(3x-2^4\right)=2.7^1\)

=> \(\left(3x-2^4\right)=14\)

=> \(3x=14+2^4\)

=> 3x = 14 + 16

     3x = 30

     x=30 : 3

     x = 10

          Vậy x = 10
#Ori_deeptry