a)

\(\left(-8537\right)+\left(1975+8537\right)\)

\(=\left(-8537\right)+1975+8537\)

\(=1975\)

b)

\(\left(35-17\right)+\left(17+20-35\right)\)

\(=35-17+17+20-35\)

\(=20\)

c)

\(273+\left[-34+27+\left(-273\right)\right]\)

\(=273-34+27-273\)

\(=27-34\)

\(=-7\)

Tham khảo:

   273 + 568 + 34

= 841 + 34

= 875

Bằng : 881 nhé

273+568+34

=841+34

=875

Nhớ tích cho em nhé

\(B=\left|157\dfrac{13}{27}-273\dfrac{7}{19}\right|-96\dfrac{14}{27}+15\dfrac{12}{19}\)

\(=273\dfrac{7}{19}-153\dfrac{13}{27}-96\dfrac{14}{27}+15\dfrac{12}{19}\)

\(=\left(273+15+\dfrac{7}{19}+\dfrac{12}{19}\right)-\left(153+96+\dfrac{13}{27}+\dfrac{14}{27}\right)\)

\(=289-250=39\)

1: \(\dfrac{f\left(x\right)}{x-3}=\dfrac{2x^2-6x+\left(a+6\right)x-3a-18+3a+19}{x-3}\)

=2x^2+(a+6)+3a+19/x-3

Để f(x)/x-3 dư 4 thì 3a+19=4

=>3a=-15

=>a=-5

2: \(\dfrac{f\left(x\right)}{x-5}=\dfrac{3x^2-15x+\left(a+15\right)x-5a-75+5a+102}{x-5}\)

\(=3x+a+15+\dfrac{5a+102}{x-5}\)

Để dư là 27 thì 5a+102=27

=>5a=-75

=>a=-15

A*27=4*273

A*27=1092

A=1092:27

A=40,44444444

bn nên xem lại đề bài đi

Đề bài sai

Sai đề rồi bạn ơi !

\(A=8^2\cdot324=8^2\cdot18^2=144^2=\left(12^2\right)^2=12^4\)

\(B=27^3\cdot9^4\cdot243=\left(3^3\right)^3\cdot\left(3^2\right)^4\cdot3^5=3^9\cdot3^8\cdot3^5=3^{22}\)

\(C=6^2\cdot36^4\cdot216^2=6^2\cdot\left(6^2\right)^4\cdot\left(6^3\right)^2=6^2\cdot6^8\cdot6^6=6^{16}\)

\(D=3^4\cdot81^2\cdot9^5=3^4\cdot\left(3^4\right)^2\cdot\left(3^2\right)^5=3^4\cdot3^8\cdot3^{10}=3^{22}\)

GẤP Ạ!!!!!!!!!!!!

Giá trị của B là 35 nha bn