thuc hien phep chia
a,(7(x^2-1)^4+2(1-x)^3-3(x-1)^2): 2(x-1)^2
b,5(x^3-y^3)+(x-y)^3:(x-y)^2
thuc hien phep tinh :
a, (x+1)(1+x-x^2+x^3-x^4)-(x-1)(1+x+x^2+x^3+x^4)
b, (2b^2-2-5b+6b^3)(3+3b^2-b)
thuc hien phep tinh :
a, (x+1)(1+x-x^2+x^3-x^4)-(x-1)(1+x+x^2+x^3+x^4)
b, (2b^2-2-5b+6b^3)(3+3b^2-b)
Bài 62 làm phép chia
a,[5.(x-y)^4-3.(x-y)^3+4.(x-y)^2]:(y-x)^2
b,[(x+y)^5-2.(x+y)^4+3.(x+y)^3]:[-5(x + y)^3]=0
thuc hien phep tinh:
(x+2)(1+x-x^2+x^3-x^4)-(1-x)(1+x+x^2+x^3+x^4)
thuc hien phep tinh:
(x+2)(1+x-x^2+x^3-x^4)-(1-x)(1+x+x^2+x^3+x^4)
thuc hien phep nhan:
(x+1)(1+x-x^2+x^3-x^4)-(x-1)(1+x+x^2+x^3+x^4)
thuc hien phep tinh:
(x+2)(1+x-x^2+x^3-x^4)-(1-x)(1+x+x^2+x^3+x^4)
thuc hien phep tinh
a.\(\left(\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}\right):\dfrac{4x}{10x-5}\)
b.\(\left(\dfrac{1}{x^2+1}-\dfrac{2-x}{x+1}\right):\left(\dfrac{1}{x}+1-2\right)\)
c.\(\dfrac{1}{x-1}-\dfrac{x^3-x}{x^2+1}.\left(\dfrac{1}{x^2-2x+1}+\dfrac{1}{1-x^2}\right)\)
d.\(\left(\dfrac{x^2+xy}{x^3+x^2y+xy^2+y^3}+\dfrac{y}{x^2+y^2}\right):\left(\dfrac{1}{x-y}-\dfrac{2xy}{x^3-x^2y+xy^2-y^3}\right)\)
a: \(=\dfrac{4x^2+4x+1-\left(4x^2-4x+1\right)}{\left(2x-1\right)\left(2x+1\right)}\cdot\dfrac{5\left(2x-1\right)}{4x}\)
\(=\dfrac{8x}{2x+1}\cdot\dfrac{5}{4x}=\dfrac{10}{2x+1}\)
c: \(=\dfrac{1}{x-1}-\dfrac{x\left(x-1\right)\left(x+1\right)}{x^2+1}\cdot\left(\dfrac{x+1-x+1}{\left(x-1\right)^2\cdot\left(x+1\right)}\right)\)
\(=\dfrac{1}{x-1}-\dfrac{x}{x^2+1}\cdot\dfrac{2}{\left(x-1\right)}=\dfrac{x^2+1-2x}{\left(x-1\right)\left(x^2+1\right)}=\dfrac{x-1}{x^2+1}\)
Bai 1: Thuc hien phep tinh
a) 2x(3x2-5 X+3). b) -2X ( x2+5x-3). c) --1/2x2(2x3-4x+3).
Bai 2 Thuc hien phep tinh.
a) (2x-1)(x2+5-4). b) -(5x-4)(2x+3). c) (2x-y)(4x2-2xy+y2).
d) (3x-4)(x+4)+(5-x)(2x2+3x-1). e)7x(x-4)-(7x+3)(2x2-x+4)
a) 2x(3x^2 -5x + 3) = 6x^3 - 10x^2 + 6x
b) -2x(x^2 +5x-3) = -2x^3 - 10x^2 + 6x
c) 2 dấu trừ liền nhau??
bài 2:
a) \(\left(2x-1\right)\left(x^2+1\right)=2x^3-x^2+2x-1\)
b) \(-\left(5x-4\right)\left(2x+3\right)=-\left(10x^2-8x+15x-12\right)=-10x^2-7x+12\)
c) \(\left(2x-y\right)\left(4x^2-2xy+y^2\right)=8x^3-4x^2y-4x^2y+2xy^2+2xy^2-y^3=8x^3-8x^2y+2xy^2-y^3\)
d) \(\left(3x-4\right)\left(x+4\right)+\left(5-x\right)\left(2x^2+3x-1\right)=3x^2+8x-16+10x^2-2x^3+15x-3x^2-5+x=10x^2+24x-21\)
e) \(7x\left(x-4\right)-\left(7x+3\right)\left(2x^2-x+4\right)=7x^2-28x-\left(14x^3+6x^2-7x^2-3x+28x+12\right)=-14x^2+8x^2-53x-12\)
\(2x\left(3x^2-5x+3\right)\)
\(=2x.3x^2-2x.5x+2x.3\)
\(=6x^3-10x^2+6x\)