thuc hien phep tinh :
a, (x+1)(1+x-x^2+x^3-x^4)-(x-1)(1+x+x^2+x^3+x^4)
b, (2b^2-2-5b+6b^3)(3+3b^2-b)
Bài 62 làm phép chia
a,[5.(x-y)^4-3.(x-y)^3+4.(x-y)^2]:(y-x)^2
b,[(x+y)^5-2.(x+y)^4+3.(x+y)^3]:[-5(x + y)^3]=0
thuc hien phep tinh:
(x+2)(1+x-x^2+x^3-x^4)-(1-x)(1+x+x^2+x^3+x^4)
Bai 1: Thuc hien phep tinh
a) 2x(3x2-5 X+3). b) -2X ( x2+5x-3). c) --1/2x2(2x3-4x+3).
Bai 2 Thuc hien phep tinh.
a) (2x-1)(x2+5-4). b) -(5x-4)(2x+3). c) (2x-y)(4x2-2xy+y2).
d) (3x-4)(x+4)+(5-x)(2x2+3x-1). e)7x(x-4)-(7x+3)(2x2-x+4)
thuc hien phep tinh:3*x^2*(6*x^(n-3)+1)-2*x^n*(9*x^(n-3)-1)
Thuc hien phep nhan rut gon roi tinh gia tri bieu thuc
B)x(x^2-y)-x^2(x+y)+y(x^2-x) tai x=1/2 va y=-100
bai 1 thuc hien phep tinh a)\(\dfrac{\left(\dfrac{1}{x^2+4x+4}-\dfrac{1}{x^2-4x+4}\right)}{\left(\dfrac{1}{x+2}+\dfrac{1}{x-2}\right)}\)
b)\(\left(\dfrac{5x+y}{x^2-5xy}+\dfrac{5x-y}{x^2+5xy}\right)\cdot\dfrac{x^2-25y^2}{x^2+y^2}\)
thuc hien phep tinh :
a, (x+1)(1+x-x\(^2\)+x\(^3\)-x\(^4\))-(x-1)(1+x+x\(^2\)+x\(^3\)+x\(^4\))
b, (2b\(^2\)-2-5b+6b\(^3\))(3+3b\(^2\)-b)
thuc hien phep chia:(x2-y2+6x+9);(x+y+3)