Bằng 0 nha bạn.

p​hân tích đa thức thành nhân tử nha

​

=2x(15a-17b)-15a+17b

=2x(15a-17b)-1(15a+17b)

=(15a-17b)(2x-1).

c)

\(30ax-34bx-15a+17b\)

\(=(30ax-15a)-(34bx-17b)\)

\(=15a(2x-1)-17b(2x-1)\)

\(=(2x-1)(15a-17b)\)

d)

\(x^3-x^2y-x^2z-xyz\)

\(=x[x^2-xy-xz-yz]\)

a)

\(12x^3+4x^2-27x-9\)

\(=(12x^3+4x^2)-(27x+9)\)

\(=4x^2(3x+1)-9(3x+1)\)

\(=(3x+1)(4x^2-9)=(3x+1)[(2x)^2-3^2]\)

\(=(3x+1)(2x-3)(2x+3)\)

b)

\(x^6-x^4+2x^3+2x^2\)

\(=x^2(x^4-x^2+2x+2)\)

\(=x^2[x^2(x^2-1)+2(x+1)]\)

\(=x^2[x^2(x-1)(x+1)+2(x+1)]\)

\(=x^2(x+1)[x^2(x-1)+2]\)

\(=x^2(x+1)[(x^3+1)-(x^2-1)]\)

\(=x^2(x+1)[(x+1)(x^2-x+1)-(x-1)(x+1)]\)

\(=x^2(x+1)(x+1)(x^2-x+1-x+1)\)

\(=x^2(x+1)^2(x^2-2x+2)\)

Phân tích đa thcusw thành nhân tử (Phương pháp nhân hạng tử):

1. 3a - 3b + ax - bx

= 3(a - b) + x(a - b)

= (a - b)(3 + x)

2. x³ + 3x² + 3x + 9

= x³ + 3x² + 3x + 1 + 8

= (x + 1)³ + 8

= (x + 1 + 2)[(x + 1)² - 2(x + 1) + 4]

= (x + 3)(x² + 2x + 1 - 2x - 2 + 4)

= (x + 3)(x² + 3)

3. 10ay - 5by + 2ax - bx

= 5y(2a - b) + x(2a - b)

= (2a - b)(5y + x)

4. 5a² - 5ax - 7a + 7x

= 5a(a - x) - 7(a - x)

= (a - x)(5a - 7)

5. x² - 3xy + x - 3x

= x(x - 3y + 1 - 3)

= x(x - 3y - 2)

6. 7x² - 7xy - 4x + 4y

= 7x(x - y) - 4(x - y)

= (x - y)(7x - 4)

7. 3ax - 4by - 4ay + 3bx

= (3ax + 3bx) - (4ay + 4by)

= 3x(a + b) - 4y(a + b)

= (a + b)(3x - 4y)

8. 30ax - 34bx - 15a + 17b

= (30ax - 15a) - (34bx -17b )

= 15a(x - 1) - 17b(x - 1)

= (x - 1)(15a - 17b)

9. 3x² - 3xy + 3y² - 3xy

= 3(x² - xy + y² - xy)

= 3(x² - 2xy + y²)

= 3(x - y)²

10. 12a² - 6ab + 3b² - 6ab

= 3(4a² - 2ab + b² - 2ab)

= 3(4a² - 4ab + b²)

= 3(2a - b)²

\(=\left(-5a\right)^3+3.\left(-5a\right)^2+3.\left(-5a\right)+1\)

\(=\left(-5a+1\right)^3\)

???giải ròi mà:

x²+5x-6

= x²-x+6x-6

= x(x-1)+6(x-1)

= (x-1).(x+6)

\(-8x^3+1=1^3-\left(2x\right)^3=\left(1-2x\right)\left(1+2x+4x^2\right)\)

a) x^2 - 2xy + y^2 - xz + yz 

= (x^2 - 2xy + y^2 ) - (xz + yz)

= (x - y)^2 - z(x + y)

= (x - y)(x - x + y)

a) x² -2x - 3

= (x² - 3x) + (x -3)

= x ( x-3) + (x - 3)

= ( x - 3)(x+1)

( Câu này bạn có thể dùng EQN để tính cho nhanh nhé)

b) a⁴+5a³+15a-9

=(a⁴-9)+(5a³+15a)

=(a²+3)(a²-3)+5a(a²+3)

=(a²+3)(a²-3+5a)

a) theo đề ta có:

x^2-2x-3=x^2-2x+1-4

              =(x-1)^2-2^2

              =(x-1-2)(x-1+2)

              =(x-3)(x+1)

\(4x\left(x-y\right)+3\left(y-x\right)^2=4x\left(x-y\right)+3\left(x-y\right)^2\)

\(=\left(x-y\right)\left[4x+3\left(x-y\right)\right]=\left(x-y\right)\left(7x-3y\right)\)

Ta có: \(4x\left(x-y\right)+3\left(y-x\right)^2\)

\(=4x\left(x-y\right)+3\left(x-y\right)^2\)

\(=\left(x-y\right)\left(4x+3x-3y\right)\)

\(=\left(x-y\right)\left(7x-3y\right)\)