e: ta có: \(4x^2+4x-6=2\)

\(\Leftrightarrow4x^2+4x-8=0\)

\(\Leftrightarrow\left(x+2\right)\left(x-1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=1\end{matrix}\right.\)

f: Ta có: \(2x^2+7x+3=0\)

\(\Leftrightarrow\left(x+3\right)\left(2x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=-3\\x=-\dfrac{1}{2}\end{matrix}\right.\)

\(a,\Leftrightarrow\left(4x-8\right)\left(x+1\right)=0\\ \Leftrightarrow4\left(x-2\right)\left(x+1\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-1\end{matrix}\right.\\ b,\Leftrightarrow\left(x+1\right)\left(x^2+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=-1\\x^2=-1\left(vô.lí\right)\end{matrix}\right.\Leftrightarrow x=-1\\ c,\Leftrightarrow x^2-2x-4x+8=0\\ \Leftrightarrow\left(x-2\right)\left(x-4\right)=0\Leftrightarrow\left[{}\begin{matrix}x=2\\x=4\end{matrix}\right.\\ d,\Leftrightarrow x^3-3x^2+3x-9x+2x-6=0\\ \Leftrightarrow\left(x-3\right)\left(x^2+3x+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x^2+x+2x+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+1\right)\left(x+2\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\\x=-2\end{matrix}\right.\)

a) \(\Rightarrow4\left(x+1\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=-1\\x=2\end{matrix}\right.\)

b) \(\Rightarrow x^2\left(x+1\right)+\left(x+1\right)=0\)

\(\Rightarrow\left(x+1\right)\left(x^2+1\right)=0\)

\(\Rightarrow x=-1\left(do.x^2+1\ge1>0\right)\)

c) \(\Rightarrow x\left(x-4\right)-2\left(x-4\right)=0\)

\(\Rightarrow\left(x-4\right)\left(x-2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=4\\x=2\end{matrix}\right.\)

d) \(\Rightarrow x^2\left(x-3\right)+3x\left(x-3\right)+2\left(x-3\right)\)

\(\Rightarrow\left(x-3\right)\left(x^2+3x+2\right)=0\)

\(\Rightarrow\left(x-3\right)\left(x+1\right)\left(x+2\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x=3\\x=-2\\x=-1\end{matrix}\right.\)

a) \(\text{5x(x-2)+(2-x)=0}\)

\(\Rightarrow5x\left(x-2\right)-\left(x-2\right)=0\\ \Rightarrow\left(x-2\right)\left(5x-1\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-2=0\\5x-1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{5}\end{matrix}\right.\)

b) \(\text{x(2x-5)-10x+25=0}\)

\(\Rightarrow x\left(2x-5\right)-5\left(2x-5\right)=0\\ \Rightarrow\left(x-5\right)\left(2x-5\right)=0\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\2x-5=0\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\\x=2,5\end{matrix}\right.\)

c) \(\dfrac{25}{16}-4x^2+4x-1=0\)

\(\Rightarrow\dfrac{9}{16}-4x^2+4x=0\)

\(\Rightarrow-4x^2+4x+\dfrac{9}{16}=0\)

\(\Rightarrow-4x^2-\dfrac{1}{2}x+\dfrac{9}{2}x+\dfrac{9}{16}=0\)

\(\Rightarrow\left(-4x^2-\dfrac{1}{2}x\right)+\left(\dfrac{9}{2}x+\dfrac{9}{16}\right)=0\)

\(\Rightarrow-\dfrac{1}{2}x\left(8x+1\right)+\dfrac{9}{16}\left(8x+1\right)=0\)

\(\Rightarrow\left(-\dfrac{1}{2}x+\dfrac{9}{16}\right)\left(8x+1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}-\dfrac{1}{2}x+\dfrac{9}{16}=0\\8x+1=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{8}\\x=\dfrac{-1}{8}\end{matrix}\right.\)

a) \(5x\left(x-2\right)+\left(2-x\right)=0\)

\(\Rightarrow5x\left(x-2\right)-\left(x-2\right)=0\)

\(\Rightarrow\left(x-2\right)\left(5x-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-2=0\\5x-1=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{1}{5}\end{matrix}\right.\)

b) \(x\left(2x-5\right)-10x+25=0\)

\(\Rightarrow x\left(2x-5\right)-5\left(2x-5\right)=0\)

\(\Rightarrow\left(x-5\right)\left(2x-5\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-5=0\\2x-5=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{5}{2}\end{matrix}\right.\)

c) \(\dfrac{25}{16}-4x^2+4x-1=0\)

\(\Rightarrow-4x^2+4x+\dfrac{9}{16}=0\)

\(\Rightarrow\left(x-\dfrac{9}{8}\right)\left(x+\dfrac{1}{8}\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{9}{8}=0\\x+\dfrac{1}{8}=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x=\dfrac{9}{8}\\x=-\dfrac{1}{8}\end{matrix}\right.\)

d) \(x^4+2x^2-8=0\)

\(\Rightarrow\left(x^4+2x^2+1\right)-9=0\)

\(\Rightarrow\left(x^2+1\right)^2-3^2=0\)

\(\Rightarrow\left(x^2+1-3\right)\left(x^2+1+3\right)=0\)

\(\Rightarrow\left(x^2-2\right)\left(x^2+4\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}x^2-2=0\\x^2+4=0\end{matrix}\right.\) \(\Rightarrow\left[{}\begin{matrix}x^2=2\\x^2=-4\end{matrix}\right.\) \(\Rightarrow x^2=2\) \(\Rightarrow x=\pm\sqrt{2}\)

a, x= 103

b, x= 3

c,x=0

Nếu thấy đúng thì k cho mk nhé!

a)7x-8=713

  7x        =713+8

   7x     =721

   x      =721:7

  x      =103

Vậy x=103

b)8(x-3)=0

     x-3=0:8

     x-3=0

     x=0+3

     x=3

Vậy x=0

4x:7=0

4x   =0*7

4x   =0

  x   =0:4

  x  =0

Vậy x=0

a/ 7x - 8 = 713

    7x      = 713 + 8

    7x      = 721

     x       = 721 : 7

     x       =  103

b/ 8 ( x -3 ) = 0

        x - 3  = 0

        x       = 0+3

        x       = 3

4x : 17 = 0

4x        = 0 x 17

4 x       = 0

   x        = 0

a) \(4x:17=0\)

\(4x=0\)

\(x=0\)

vay \(x=0\)

b) \(7x-8=713\)

\(7x=713+8\)

\(7x=721\)

\(x=103\)

vay \(x=103\)

c) \(8\left(x-3\right)=0\)

\(8x-24=0\)

\(8x=24\)

\(x=3\)

vay \(x=3\)

d) \(0:x=0\)

\(\Rightarrow x\in R\) va \(x\ne0\)

vay \(x\in R\)va \(x\ne0\)

a)x=0

b)x=103

c)x=3

d)x thuộc R

a, 4x : 17 = 0

=>4x        = 0

      x        = 0 : 4

      x         = 0

Vậy x = 0 .

b, 7x - 8 = 713

   7x      = 713 + 8

    7x     = 721

      x     = 721 : 7

      x     = 103

Vậy x = 103 .

c, 8( x - 3 ) = 0

=>   x - 3    = 0

       x         = 0 + 3

       x         = 3

Vậy x = 3 .

d, 0 : x = 0 

=> x là các số tự nhiên khác 0 

=> X ∈ N*

Chúc học tốt !

a) 4X : 17 = 0

             4X= 0 x17

             4X = 0

               X = 0 : 4

               X = 0

Vậy X = 0

b) 7X - 8 = 713

          7X = 713 + 8

           7X = 721

              X = 721 : 7

              X = 103

Vậy X = 103

c) 8 ( X - 3 ) = 0

          X - 3   = 0 : 8

          X - 3   = 0

                  X = 0 + 3

                  X = 3

Vậy X = 3

a. 4x : 17 = 0

=> 4x=0.17

=> 4x=0

=> x=0:4

=> x=0

b. 7x - 8 = 713

=> 7x=713+8

=> 7x = 721

=> x = 721 : 7

=> x= 103

c. 8(x - 3) = 0

=> x-3=0:8

=> x-3=0

=> x=0+3

=> x=3

a. 4x : 17= 0

     4x       = 0 : 17

     4x       =   0

       x       = 0 : 4

       x      = 0

b. 7x - 8 = 713

    7x       =  713 + 8

     7x      = 721

       x      = 721 : 7

      x       = 103

c . 8 ( x - 3 ) = 0

         x - 3     = 0 : 8

         x  - 3    = 0

         x          = 0 + 3

        x           =   3

Bài 1.

a) 4x:17=0

    4x=0x17

    4x=0

      x=0:4

       x=0

b)7x-8=713

7x=213+8

7x=221

  x=221:7

  x=221/7

c)8(x-3)=0

8x - 8x3 = 0

8x -24=0

8x=0+24

8x=24

  x=24:8

   x=3