Tìm x biết:
a, (-3x + 3)(-2x - 2)\(\le\)0
b, (\(\frac{1}{2}\)- 2x)(\(\frac{1}{2}\)+ 3x)\(\ge\)0
Những câu hỏi liên quan
bài 1: giải các bất phương trình sau:
1) (x-3)(4-x)≥0
2) frac{1+2x}{3x-4} 0
3) (x+1)(x-1)(3x-6)0
4) 3x(2x+7)(9-3x)≥0
5) frac{left(2x-5right)left(x+2right)}{-4x+3}0
6) frac{2}{x-1}lefrac{5}{2x-1}
7) frac{x-3}{x+1}frac{x+5}{x-2}
8) frac{2x^2+x}{1-2x}ge1-x
Đọc tiếp
bài 1: giải các bất phương trình sau:
1) (x-3)(4-x)≥0
2) \(\frac{1+2x}{3x-4}< 0\)
3) (x+1)(x-1)(3x-6)>0
4) 3x(2x+7)(9-3x)≥0
5) \(\frac{\left(2x-5\right)\left(x+2\right)}{-4x+3}>0\)
6) \(\frac{2}{x-1}\le\frac{5}{2x-1}\)
7) \(\frac{x-3}{x+1}>\frac{x+5}{x-2}\)
8) \(\frac{2x^2+x}{1-2x}\ge1-x\)
giải các bất phương trình sau:
a) 2x-\(\frac{4x}{1-x}< \frac{4}{x-1}-2\)
b) \(\frac{2}{x-1}\le\frac{5}{2x-1}\)
c) \(\frac{3}{3x^2+x-4}\ge\frac{1}{x^2-4}\)
d) (x-2)(9-x2)≤0
e) (x2-x-6)(x2-3x+2)≥0
SGK Cánh Diều
13 tháng 8 2023 lúc 21:30
Đề bài
Giải mỗi bất phương trình sau:
a) \({3^x} > \frac{1}{{243}}\)
b) \({\left( {\frac{2}{3}} \right)^{3x - 7}} \le \frac{3}{2}\)
c) \({4^{x + 3}} \ge {32^x}\)
d) \(\log (x - 1) < 0\)
e) \({\log _{\frac{1}{5}}}(2x - 1) \ge {\log _{\frac{1}{5}}}(x + 3)\)
f) \(\ln (x + 3) \ge \ln (2x - 8)\)
\(a,3^x>\dfrac{1}{243}\\ \Leftrightarrow3^x>3^{-5}\\ \Leftrightarrow x>-5\\ b,\left(\dfrac{2}{3}\right)^{3x-7}\le\dfrac{3}{2}\\ \Leftrightarrow3x-7\le1\\ \Leftrightarrow3x\le8\\ \Leftrightarrow x\le\dfrac{8}{3}\\ c,4^{x+3}\ge32^x\\ \Leftrightarrow2^{2x+6}\ge2^{5x}\\ \Leftrightarrow2x+6\ge5x\\ \Leftrightarrow3x\le6\\ \Leftrightarrow x\le2\)
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d, Điều kiện: x > 1
\(log\left(x-1\right)< 0\\ \Leftrightarrow x-1< 1\\ \Leftrightarrow1< x< 2\)
e, Điều kiện: \(x>\dfrac{1}{2}\)
\(log_{\dfrac{1}{5}}\left(2x-1\right)\ge log_{\dfrac{1}{5}}\left(x+3\right)\\ \Leftrightarrow2x-1\ge x+3\\ \Leftrightarrow x\ge4\)
f, Điều kiện: x > 4
\(ln\left(x+3\right)\ge ln\left(2x-8\right)\\ \Leftrightarrow x+3\ge2x-8\\\Leftrightarrow4< x\le11\)
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giải các bất đẳng thức sau:
1) \(\frac{3x-4}{x-2}\)>1
2) \(\frac{2x-5}{2-x}\)≤ -1
3) \(\frac{x^2+x-3}{x^2-4}\)≤ 1
4) \(\frac{2x^2-4x+3}{x^2-x-6}+\frac{1}{2}\)> 0
5) \(\frac{x^2+3x+2}{2x+3}\)≥\(\frac{2x-5}{4}\)
giúp mình với mng!!!
a/
\(\frac{3x-4}{x-2}-1>0\Leftrightarrow\frac{2x-2}{x-2}>0\Rightarrow\left[{}\begin{matrix}x>2\\x< 1\end{matrix}\right.\)
b/
\(\frac{2x-5}{2-x}+1\le0\Rightarrow\frac{x-3}{2-x}\le0\Rightarrow\left[{}\begin{matrix}x\ge3\\x< 2\end{matrix}\right.\)
c/
\(\frac{x^2+x-3}{x^2-4}-1\le0\Rightarrow\frac{x+1}{x^2-4}\le0\Rightarrow\frac{x+1}{\left(x-2\right)\left(x+2\right)}\le0\Rightarrow\left[{}\begin{matrix}x< -2\\-1\le x< 2\end{matrix}\right.\)
d/
\(\frac{4x^2-8x+6+x^2-x-6}{2\left(x^2-x-6\right)}>0\Rightarrow\frac{x\left(5x-9\right)}{2\left(x+2\right)\left(x-3\right)}>0\Rightarrow\left[{}\begin{matrix}x>3\\0< x< \frac{9}{5}\\x< -2\end{matrix}\right.\)
e/
\(\frac{x^2+3x+2}{2x+3}-\frac{2x-5}{4}\ge0\Rightarrow\frac{4x^2+12x+8-\left(2x-5\right)\left(2x+3\right)}{4\left(2x+3\right)}\ge0\)
\(\Rightarrow\frac{28x+23}{4\left(2x+3\right)}\ge0\Rightarrow\left[{}\begin{matrix}x\ge-\frac{23}{28}\\x< -\frac{3}{2}\end{matrix}\right.\)
Giải các bất phương trình sau:
a) \(\frac{3}{x}< \frac{1}{x}+\frac{2}{x+4}\)
b) \(\frac{x^2+x-3}{x^2-4}\ge1\)
c) \(\frac{3}{2x-1}\ge-\frac{1}{x+2}\)
d) \(\frac{2x-1}{3x+2}\le\frac{3x+2}{2x-1}\)
Câu 1: Xét dấu các biểu thức sau:
a, f(x)frac{x-1}{left(x+3right)left(2x-1right)}
b, f(x)(3x-1)(x2-4)
c, f(x)frac{left(3x-1right)left(5-2xright)}{left(x+2right)left(x+5right)}
Câu 2: Giải các bất phương trình:
a, (x-1)(x-2) ≥ 0
b, (3-x)(x+5) ≤ 0
c, frac{2}{4-x} ≤ 1
d, frac{4-3x}{x-2} ≥ 3
Đọc tiếp
Câu 1: Xét dấu các biểu thức sau:
a, f(x)=\(\frac{x-1}{\left(x+3\right)\left(2x-1\right)}\)
b, f(x)=(3x-1)(x2-4)
c, f(x)=\(\frac{\left(3x-1\right)\left(5-2x\right)}{\left(x+2\right)\left(x+5\right)}\)
Câu 2: Giải các bất phương trình:
a, (x-1)(x-2) ≥ 0
b, (3-x)(x+5) ≤ 0
c, \(\frac{2}{4-x}\) ≤ 1
d, \(\frac{4-3x}{x-2}\) ≥ 3
@Akai Haruma cô giúp em với ạ
1.Giải các phuong trình sau:
A. 5x -20 \(\le\)0
B.3x+7 > -7x+2
C. -9x-5 <4x +21
D. 3(2x-5) >8x-13
E. 2(3x-5) \(\ge\)5(2x+6)
F.\(\frac{2x-3}{4}\)\(\le\)\(\frac{3x+1}{6}\)
H.2x+3(x-3)\(\ge\)10x-(3x+2)
Help me
a) \(5x-20\le0\\ \Leftrightarrow5x\le20\\ \Leftrightarrow x\le\frac{20}{5}\\ \Leftrightarrow x\le4\)
b)\(3x+7>-7x+2\\ \Leftrightarrow3x+7x>2-7\\ \Leftrightarrow10x>-5\\ \Leftrightarrow x>-\frac{5}{10}\\ \Leftrightarrow x>-\frac{1}{2}\)
c)\(-9x-5< 4x+21\\ \Leftrightarrow-9x-4x< 21+5\\ \Leftrightarrow-13x< 26\\ \Leftrightarrow x>\frac{-26}{13}\\ \Leftrightarrow x>-2\)
d) 3(2x-5) >8x-13
<=> 6x -15> 8x-13
<=> 6x-8x>-13+15
<=>-2x>2
<=> x< -2/2
<=>x<-1
e) \( 2(3x-5) ≥ 5(2x+6)\\ \Leftrightarrow6x-10\ge10x+30\\ \Leftrightarrow6x-10x\ge30+10\\ \Leftrightarrow-4x\ge40\\ \Leftrightarrow x\le-\frac{40}{4}\\ \Leftrightarrow x\le-10\)
f) \(\frac{2x-3}{4}\le\frac{3x+1}{6}\\ \Leftrightarrow\frac{3.\left(2x-3\right)}{12}\le\frac{2.\left(3x+1\right)}{12}\\ \Leftrightarrow6x-9\le6x+2\\ \Leftrightarrow6x-6x\le2+9\\ \Leftrightarrow0x\le11\)
=>Luôn đúng => Bpt vô số nghiệm
h. Ta có : \(2x+3\left(x-3\right)\ge10x-\left(3x+2\right)\)
=> \(2x+3x-9\ge10x-3x-2\)
=> \(2x+3x-9-10x+3x+2\ge0\)
=> \(-2x-7\ge0\)
=> \(x\ge-\frac{7}{2}\)
1. Cho a,b ge0 và a+ble2 . Chứng minh frac{2+alpha}{1+alpha}+frac{1-2b}{1+2b}gefrac{8}{7}2. Tìm x: frac{frac{2x-1}{2}-3}{4}-frac{4-frac{1+2x}{3}}{2}frac{5-frac{1}{2}X}{6}-33.tìm x: left(x-2right)^2-3left(x-1right)+2x^2left(x-1right)left(2x+1right)^2+2left(x^3-2right)4. Rút Gọn B left(frac{X+2}{X+1}-frac{2X}{X-1}right)divfrac{X}{3X+3}+frac{4X^2+X+7}{X^2-X}
Đọc tiếp
1. Cho a,b \(\ge\)0 và a+b\(\le\)2 . Chứng minh \(\frac{2+\alpha}{1+\alpha}+\frac{1-2b}{1+2b}\ge\frac{8}{7}\)
2. Tìm x: \(\frac{\frac{2x-1}{2}-3}{4}-\frac{4-\frac{1+2x}{3}}{2}=\frac{5-\frac{1}{2}X}{6}-3\)
3.tìm x: \(\left(x-2\right)^2-3\left(x-1\right)+2x^2\left(x-1\right)=\left(2x+1\right)^2+2\left(x^3-2\right)\)
4. Rút Gọn B = \(\left(\frac{X+2}{X+1}-\frac{2X}{X-1}\right)\div\frac{X}{3X+3}+\frac{4X^2+X+7}{X^2-X}\)
giai bat phuong trinh
c) \(\frac{(3x-2)^2}{3}-\frac{\left(2x+1\right)^2}{3}\le x\left(x+1\right)\)
d) \(\frac{2x-3}{4}-\frac{x+1}{3}\ge\frac{1}{2}-\frac{3-x}{5}\)