cùng một cơ số*

\(6^{15}\cdot6^2=6^{17}\\ 3^{14}\cdot2^{14}=\left(3\cdot2\right)^{14}=6^{14}\\ 2^{11}\cdot6^3\cdot3^{11}=\left(2\cdot3\right)^{11}\cdot6^3=6^{11}\cdot6^3=6^{14}\\ 6^2\cdot6^7=6^{13}\\ \left(6^3\right)^4=6^{3\cdot4}=6^{12}\\ 6^{2^3}=6^8\)

3^6 . 9^5

= 3^6. \(^{\left(3^2\right)^5}\)

= 3^6. 3^10

=\(^{3^{6+10}}\)

= 3^16

k nhé ( dấu " ^"  là đấu mũ)

3^6 x 9^5 = 3^6 x ( 3^2)^5 = 3^6 x 3^10 = 3^16

3^6.9^5=3^6.(3²)^5=3^6.3^10=3¹⁰⁺⁶=3¹⁶

\(\left(0,25\right)^8=\left[\left(0,5\right)^2\right]^8=\left(0,5\right)^{2.8}=\left(0,5\right)^{16}\)

\(\left(0,125\right)^4=\left[\left(0,5\right)^3\right]^4=\left(0,5\right)^{3.4}=\left(0,5\right)^{12}\)

\(\left(0,0635\right)^2=\left[\left(0,5\right)^3\right]^2=\left(0,5\right)^{3.2}=\left(0,5\right)^6\)

\(9^2=\left(3^2\right)^2=3^{2\cdot2}=3^4\)

Ta có: (-8).(-3)3.(+125)

= (-2)3 . (-3)3 . 53

= [(-2).(-3)]3.53 = 63 . 53

= (6.5)3 = 303

Ta có: 27.(-2)3.(-7).(+49)

= 33 . (-2)3 . (-7) . (-7)2

= 33 . (-2)3 . (-7)3 = [3 . (-2) . (-7)]3 = 423

(Lưu ý: 49 = (-7)) . (-7) = (-7)2

1= 30; 243 = 35; 1/3 = 3-1; 1/9 = 3-2

\(16.32=2^4.2^5=2^9\)

16.32=2^4.2^5=2^9

4^2.2^2.8

\(A=8^2\cdot32^4\\ =2^6\cdot2^{20}\\ =2^{26}\\ B=27^3\cdot9^4\cdot243\\ =3^9\cdot3^{12}\cdot3^5\\ =3^{26}\)

`A=8^2*32^4=(2^3)^2*(2^5)^4=2^6*2^20=2^26`

`B=27^3*9^4*243=(3^3)^3*(3^2)^4*3^5=3^9*3^8*3^5=3^22`

\(A=8^2.32^4\)

\(=\left(2^3\right)^2.\left(2^5\right)^4\)

\(=2^6.2^{20}\)

\(=2^{26}\)

\(B=27^3.9^4.243\)

\(=\left(3^3\right)^3.\left(3^2\right)^4.3^5\)

\(=3^9.3^8.3^5\)

\(=3^{22}\)

8=2^3 
16=4^2 
27=3^3 
64=8^2 
81=9^2 
100=10^2 
vay cac so co dang luy thua cua 1 so tu nhien lon hon 1 la :8 , 16 , 27 , 64, 81 , 100.

các số dạng lũy thừa của 1 số tự nhiên lớn hơn 1 là:8,16,27,64,81,100

Tính : 10^{2 ;}