Cứu điii ạaa, bài nào cũng được nhma mấy ac chỉ bằng kiến thức lớp 6 nhé ạaa, CẢM ƠN NHIỀUUU ẠAA WẢ ÁI NỊII:3
Giúp vs ạaa cảm ơn mấy thầy cô nhìu ạ
where my father worked then
the good performance, she lost the match
, who sings Western folk songs very well, can compost songs
the first time I've ever read such an interesting book
where my father worked then
the good performance, she lost the match
, who sings Western folk songs very well, can compost songs
the first time I've ever read such an interesting book
mọi người giải giúp mik bài 5 vs 6 đi ạ, mai mik nộp rùi, cảm ơn mọi người nhìu ạaa
cảm ơn ạaa
Câu 22:
\(n_{CH_3COOH}=\dfrac{45}{60}=0,75\left(mol\right)\)
PT: \(CH_3COOH+C_2H_5OH⇌CH_3COOC_2H_5+H_2O\) (xt: H2SO4, to)
Theo PT: \(n_{CH_3COOC_2H_5\left(LT\right)}=n_{CH_3COOH}=0,75\left(mol\right)\)
Mà: H = 80%
\(\Rightarrow n_{CH_3COOC_2H_5\left(TT\right)}=0,75.80\%=0,6\left(mol\right)\)
\(\Rightarrow m_{CH_3COOC_2H_5\left(TT\right)}=0,6.88=52,8\left(g\right)\)
Câu 23:
mCaCO3 = 20.80% = 16 (g) \(\Rightarrow n_{CaCO_3}=\dfrac{16}{100}=0,16\left(mol\right)\)
PT: \(CaCO_3+2CH_3COOH\rightarrow\left(CH_3COO\right)_2Ca+CO_2+H_2O\)
a, Theo PT: \(n_{CH_3COOH}=2n_{CaCO_3}=0,32\left(mol\right)\Rightarrow m_{CH_3COOH}=0,32.60=19,2\left(g\right)\)
b, \(n_{CO_2}=n_{CaCO_3}=0,16\left(mol\right)\Rightarrow V_{CO_2}=0,16.22,4=3,584\left(l\right)\)
em cảm ơn ạaa
em cảm ơn ạaa
16 C
17 A
18 B
19 A
20 C
21 B
22 B
23 C
24 B
25 D
26 D
27 B
28 C
29 A
30 D
31 C
em cảm ơn ạaa
Ta có: \(7x+4=x-2m\left(1\right)\)
Thay \(x=6\) vào \(\left(1\right)\) ta có:
\(7.6+4=6-2m\)
\(\Rightarrow46=6-2m\)
\(\Rightarrow-2m=40\)
\(\Rightarrow m=-20\)
cảm ơn nhiều ạaa
a: Xét ΔEBF và ΔECD có
\(\widehat{EBF}=\widehat{ECD}\)(hai góc so le trong, BF//CD)
\(\widehat{BEF}=\widehat{CED}\)(hai góc đối đỉnh)
Do đó: ΔEBF~ΔECD(2)
Xét ΔEBF và ΔDAF có
\(\widehat{F}\) chung
\(\widehat{EBF}=\widehat{DAF}\)(hai góc đồng vị, BE//AD)
Do đó: ΔEBF~ΔDAF(1)
Từ (1) và (2) suy ra ΔECD~ΔDAF
b: BE+CE=BC
=>BE+4=6
=>BE=2(cm)
Xét ΔFAD có BE//AD
nên \(\dfrac{FB}{FA}=\dfrac{EB}{AD}\)
=>\(\dfrac{FB}{BF+15}=\dfrac{2}{6}=\dfrac{1}{3}\)
=>\(3BF=BF+15\)
=>2BF=15
=>BF=7,5(cm)
AF=AB+BF=15+7,5=22,5(cm)
c: Ta có: ΔECD~ΔDAF
=>\(\dfrac{EC}{DA}=\dfrac{DE}{DF}\)
=>\(EC\cdot DF=DE\cdot DA\)
Ta có: ΔECD~ΔDAF
=>\(\dfrac{CD}{AF}=\dfrac{EC}{DA}\)
=>\(EC\cdot AF=CD\cdot DA\)
cho e hỏi mấy ac lớp 9 là văn 8 giữa kì 2 thì nó những dạng như nào ạ mà có bắt buộc phải học bài thơ k ạ còn tlv thì nó ra dạng gì thế ạaa. Mog ac repp huhu
giúp mình với, cảm ơn ạaa
1 I'd rather you didn't go out this Christmas
2 I'd rather the children went to bed
3 I'd rather you helped your mother with housework
4 I'd rather you didn't come to class late
5 I'd rather you kept silent in the classroom
It's time
1 It's time for you to dress yourself
2 It's about time the children went to bed
3 It's time we hurried up or we will be late for the train
4 It's high time children went to bed
5 It's about time for us to go home