cần giúp gấp vs ạ, em cảm ơn nhìu
cần giúp gấp vs ạ , em cảm ơn nhìu
c/
$C=\frac{11}{2}(\frac{2}{1.3}+\frac{2}{3.5}+...+\frac{2}{91.93})$
$=\frac{11}{2}\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+...+\frac{93-91}{91.93}\right)$
$=\frac{11}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+....+\frac{1}{91}-\frac{1}{93}\right)$
$=\frac{11}{2}(1-\frac{1}{93})$
$=\frac{11}{2}.\frac{92}{93}=\frac{506}{93}$
d/
$D=5\left(\frac{1}{3}+\frac{1}{15}+\frac{1}{35}+...+\frac{1}{675}\right)$
$=\frac{5}{2}\left(\frac{2}{3}+\frac{2}{15}+\frac{2}{35}+...+\frac{2}{675}\right)$
$=\frac{5}{2}\left(\frac{3-1}{1.3}+\frac{5-3}{3.5}+\frac{7-5}{5.7}+...+\frac{27-25}{25.27}\right)$
$=\frac{5}{2}\left(1-\frac{1}{3}+\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+...+\frac{1}{25}-\frac{1}{27}\right)$
$=\frac{5}{2}\left(1-\frac{1}{27}\right)$
$=\frac{5}{2}.\frac{26}{27}=\frac{65}{27}$
e/
$E=13\left(\frac{1}{15}+\frac{1}{35}+\frac{1}{63}...+\frac{1}{1023}\right)$
$=\frac{13}{2}\left(\frac{2}{15}+\frac{2}{35}+\frac{2}{63}+...+\frac{2}{1023}\right)$
$=\frac{13}{2}\left(\frac{5-3}{3.5}+\frac{7-5}{5.7}+\frac{9-7}{7.9}+...+\frac{33-31}{31.33}\right)$
$=\frac{13}{2}\left(\frac{1}{3}-\frac{1}{5}+\frac{1}{5}-\frac{1}{7}+\frac{1}{7}-\frac{1}{9}+...+\frac{1}{31}-\frac{1}{33}\right)$
$=\frac{13}{2}(\frac{1}{3}-\frac{1}{33})=\frac{65}{33}$
$=\frac{5}{2}.\frac{26}{27}=\frac{65}{27}$
Giải chi tiết giúp e vs ạ. Em cần gấp ạ. Cảm ơn nhìu 💞
Xet tam giac BDC va tam giac CEB ta co
^BDC = ^CEB = 900
BC _ chung
^BCD = ^CBE ( gt )
=> tam giac BDC = tam giac CEB ( ch - gn )
=> ^DBC = ^ECB ( 2 goc tuong ung )
Ta co ^B - ^DBC = ^ABD
^C - ^ECB = ^ACE
=> ^ABD = ^ACE
Xet tam giac IBE va tam giac ICD
^ABD = ^ACE ( cmt )
^BIE = ^CID ( doi dinh )
^BEI = ^IDC = 900
Vay tam giac IBE = tam giac ICD (g.g.g)
c, Do BD vuong AC => BD la duong cao
CE vuong BA => CE la duong cao
ma BD giao CE = I => I la truc tam
=> AI la duong cao thu 3
=> AI vuong BC
MN GIÚP EM BÀI NÀY VS Ạ
EM CẢM ƠN RẤT NHÌU
(ĐAG CẦN GẤP)
Giúp em bài 8 vs ạ em đang cần gấp pleaseeeeeeeee Giải chi tiết ra giùm em ạ em cảm ơn nhìu
Mọi người giúp e vs ạ, đang cần gấp lắm. Em cảm ơn nhìu :3333
8. As it is raining heavily, we can't go on a picnic
9. I suggest (that) you should get a plumber to check the pipes
10. If you don't succeed, you'll have to try it again
11. If she had enough money, she would buy the dictionary
12. I suggest using gas instead of burning coal
13. I suggest you should install a burglar alarm in your house
14. If we recycle, we will save natural resources
15. If you don't hurry up, you will be late for work
16. If you work too much, you will be tired
17. I suggest putting different kinds of.....
18. Lan broke the glass as she was careless
19. If you litter the place around you, it will be a junk yard
20. Paul suggested using public transportation
21. If she doesn't reduce the use of water and electricity, she will have to.....
22. Since the weather was snowy, we postponed our soccer match
23. Tan suggested that Lam should buy a car
24. Lan suggested that I should look for another job
25. The scientist suggested using public transportation instead of private vehicles
26. giống c12
27. The principle is pleased that the students in grade 9 are good helpers
28. If we put garbage into the bins, we will minimize pollution
29. If you are careless, you will broke the vase
30. If you don't stop cutting trees, I will call the police
31. If you use electricity to catch fish, you will be fined heavily
32. I'm sure that that boy will have a test.....
33. We are disappointed that you threw the rubbish on the street
34. It is extremely important that all of us work together to protect the environment
35. I'm sorry that I couldn't do anything to help you
36. He is sure that environmental pollution in this area can be controlled
37. She was annoyed that he damaged the car yesterday
Giúp em với ạ. Làm ơn. Cần gấp. Em cảm ơn nhìu ạ
Ai lm giúp mik bài 2 vs ạ Mik đang cần gấp ạ Cảm ơn nhìu
Bài 2:
a: Xét ΔABC có
X là trung điểm của BC
Y là trung điểm của AB
Do đó: XY là đường trung bình
=>XY//AC và XY=AC/2=3,5(cm)
hay XZ//AC và XZ=AC
b: Xét tứ giác AZBX có
Y là trung điểm của AB
Y là trung điểm của ZX
Do đó: AZBX là hình bình hành
mà \(\widehat{AXB}=90^0\)
nên AZBX là hình chữ nhật
d: Xét tứ giác AZXC có
XZ//AC
XZ=AC
Do đó: AZXC là hình bình hành
mn giúp em vs ạ em cảm ơn nhìu em đang cần gấp
giúp mik vs. mik cần gấp ạ. trả lời nhanh nha. cảm ơn nhìu.