Tính.
a) $\frac{1}{4}$ của 12
b) $\frac{3}{5}$ của 20
c) $\frac{5}{8}$ của 32
d) $\frac{4}{7}$ của 35
Tính.
a) $\frac{1}{6}:\frac{3}{7}$
b) $\frac{5}{{12}}:\frac{1}{4}$
c) $\frac{4}{{15}}:\frac{8}{3}$
d) $\frac{{18}}{5}:\frac{9}{{10}}$
a) $\frac{1}{6}:\frac{3}{7} = \frac{1}{6} \times \frac{7}{3} = \frac{7}{{18}}$
b) $\frac{5}{{12}}:\frac{1}{4} = \frac{5}{{12}} \times \frac{4}{1} = \frac{{5 \times 4}}{{12 \times 1}} = \frac{{5 \times 4}}{{4 \times 3 \times 1}} = \frac{5}{3}$
c) $\frac{4}{{15}}:\frac{8}{3} = \frac{4}{{15}} \times \frac{3}{8} = \frac{{4 \times 3}}{{15 \times 8}} = \frac{{4 \times 3}}{{5 \times 3 \times 4 \times 2}} = \frac{1}{{10}}$
d) $\frac{{18}}{5}:\frac{9}{{10}} = \frac{{18}}{5} \times \frac{{10}}{9} = \frac{{18 \times 10}}{{5 \times 9}} = \frac{{9 \times 2 \times 5 \times 2}}{{5 \times 9}} = 4$
Tính.
a) $\frac{3}{4}$ của 24 kg
b) $\frac{5}{{12}}$ của 60 $\ell $
c) $\frac{3}{{10}}$ của 1 000 g
d) $\frac{2}{7}$ của 56 m2
a) $\frac{3}{4}$ của 24 kg là $24 \times \frac{3}{4} = 18$ (kg)
b) $\frac{5}{{12}}$ của 60 $\ell $ là $60 \times \frac{5}{{12}} = 25$ ($\ell $)
c) $\frac{3}{{10}}$ của 1 000 g là $1\,000 \times \frac{3}{{10}} = 300$ (g)
d) $\frac{2}{7}$ của 56 m2 là $56 \times \frac{2}{7} = 16$ (m2)
Tính.
a) $\frac{1}{6} \times \frac{2}{3}$
b) $\frac{6}{5} \times \frac{3}{8}$
c) $\frac{4}{3} \times \frac{8}{9}$
d) $\frac{5}{{12}} \times \frac{{12}}{5}$
a) $\frac{1}{6} \times \frac{2}{3} = \frac{{1 \times 2}}{{6 \times 3}} = \frac{2}{{18}} = \frac{1}{9}$
b) $\frac{6}{5} \times \frac{3}{8} = \frac{{6 \times 3}}{{5 \times 8}} = \frac{{18}}{{40}} = \frac{9}{{20}}$
c) $\frac{4}{3} \times \frac{8}{9} = \frac{{4 \times 8}}{{3 \times 9}} = \frac{{32}}{{27}}$
d) $\frac{5}{{12}} \times \frac{{12}}{5} = \frac{{5 \times 12}}{{12 \times 5}} = \frac{{60}}{{60}} = 1$
Tính.
a) \(\frac{{ - 2}}{7}:\frac{4}{7}\) b) \(\frac{{ - 4}}{5}:\frac{{ - 3}}{{11}}\)
c) \(4:\frac{{ - 2}}{5}\) d) \(\frac{{15}}{{ - 8}}:6\)
a) \(\frac{{ - 2}}{7}:\frac{4}{7} = \frac{{ - 2}}{7}.\frac{7}{4} = \frac{{ - 2}}{4} = \frac{{ - 1}}{2}\)
b) \(\frac{{ - 4}}{5}:\frac{{ - 3}}{{11}} = \frac{{ - 4}}{5}.\frac{{11}}{{ - 3}} = \frac{{ - 44}}{{ - 15}} = \frac{{44}}{{15}}\)
c) \(4:\frac{{ - 2}}{5} = 4.\frac{5}{{ - 2}} = \frac{{20}}{{ - 2}} = - 10\)
d) \(\frac{{15}}{{ - 8}}:6 = \frac{{15}}{{ - 8}}.\frac{1}{6} = \frac{{ - 15}}{{48}}= \frac{{ - 5}}{{16}}\).
a) \(\dfrac{-2}{7}:\dfrac{4}{7}=\dfrac{-2}{7}.\dfrac{7}{4}=\dfrac{-2.7}{7.4}=\dfrac{-1}{2}\)
b) \(\dfrac{-4}{5}:\dfrac{-3}{11}=\dfrac{-4}{5}.\dfrac{-11}{3}=\dfrac{-4.\left(-11\right)}{5.3}=\dfrac{44}{15}\)
c) \(4:\dfrac{-2}{5}=4.\dfrac{-5}{2}=\dfrac{4.\left(-5\right)}{2}=-10\)
d) \(\dfrac{15}{-8}:6=\dfrac{-15}{8}.\dfrac{1}{6}=\dfrac{-15}{8.6}=\dfrac{-5}{16}\)
Tính.
a) $\frac{4}{{25}}:\frac{4}{3}$
b) $\frac{3}{{14}}:\frac{6}{7}$
c) $\frac{{12}}{{15}}:2$
d) $\frac{{21}}{8}:6$
a) $\frac{4}{{25}}:\frac{4}{3} = \frac{4}{{25}} \times \frac{3}{4} = \frac{3}{{25}}$
b) $\frac{3}{{14}}:\frac{6}{7} = \frac{3}{{14}} \times \frac{7}{6} = \frac{{3 \times 7}}{{14 \times 6}} = \frac{{3 \times 7}}{{7 \times 2 \times 3 \times 2}} = \frac{1}{4}$
c) $\frac{{12}}{{15}}:2 = \frac{{12}}{{15}} \times \frac{1}{2} = \frac{{12 \times 1}}{{15 \times 2}} = \frac{{6 \times 2 \times 1}}{{15 \times 2}} = \frac{6}{{15}}$
d) $\frac{{21}}{8}:6 = \frac{{21}}{8} \times \frac{1}{6} = \frac{{21 \times 1}}{{8 \times 6}} = \frac{{7 \times 3 \times 1}}{{8 \times 3 \times 2}} = \frac{7}{{16}}$
bài 1 : tính phân số:
a) \(\frac{5}{7}+\frac{4}{9}=?;\frac{4}{5}-\frac{2}{3}=?;\frac{9}{11}+\frac{3}{8}=?;\frac{16}{25}-\frac{2}{5}=?\)=?
b)\(5+\frac{3}{5}=?;10-\frac{9}{16}=?;\frac{2}{3}-\left(\frac{1}{6}+\frac{1}{8}\right)=?\)
c)\(\frac{5}{7}+\frac{7}{6}=?;\frac{7}{12}+\frac{17}{18}=?;\frac{9}{8}+\frac{15}{32}=?;4+\frac{35}{45}=?\)
d)\(\frac{11}{4}-\frac{15}{16}=?;\frac{5}{6}-\frac{5}{8}=?;\frac{196}{64}-2=?;3-\frac{13}{9}=?\)
e)\(\frac{8}{5}+\frac{7}{6}+\frac{5}{9}-2=?;3-\frac{5}{6}-\frac{4}{9}+\frac{32}{24}=?\)
a)\(\dfrac{5}{7}+\dfrac{4}{9}=\dfrac{45}{63}+\dfrac{28}{63}=\dfrac{73}{63}\) ; \(\dfrac{9}{11}+\dfrac{3}{8}=\dfrac{72}{88}+\dfrac{33}{88}=\dfrac{105}{88}\)
\(\dfrac{4}{5}-\dfrac{2}{3}=\dfrac{12}{15}-\dfrac{10}{15}=\dfrac{2}{15}\); \(\dfrac{16}{25}-\dfrac{2}{5}=\dfrac{16}{25}-\dfrac{10}{25}=\dfrac{6}{25}\)
Tính hợp lý giá trị của biểu thức sau:
\(A=49\frac{8}{23}-\left(5\frac{7}{32}+14\frac{8}{23}\right)\)
\(B=71\frac{38}{45}-\left(43\frac{8}{45}-1\frac{17}{57}\right)\)
\(C=\frac{-3}{7}.\frac{5}{9}+\frac{4}{9}.\frac{-3}{7}+2\frac{3}{7}\)
\(D=\left(19\frac{5}{8}:\frac{7}{12}-13\frac{1}{4}:\frac{7}{12}\right).\frac{4}{5}\)
Tính giá trị của biểu thức sau (tính hợp lí, nếu có thể):
a) \(\frac{{ - 3}}{7}.\frac{2}{5} + \frac{2}{5}.\left( { - \frac{5}{{14}}} \right) - \frac{{18}}{{35}}\)
b) \(\left( {\frac{2}{3} - \frac{5}{{11}} + \frac{1}{4}} \right):\left( {1 + \frac{5}{{12}} - \frac{7}{{11}}} \right)\);
c) \(\left( {13,6 - 37,8} \right).\left( { - 3,2} \right)\)
d) \(\left( { - 25,4} \right).\left( {18,5 + 43,6 - 16,8} \right):12,7\)
a) \(\frac{{ - 3}}{7}.\frac{2}{5} + \frac{2}{5}.\left( { - \frac{5}{{14}}} \right) - \frac{{18}}{{35}}\)
\(\begin{array}{l} = \frac{2}{5}.\left( {\frac{{ - 3}}{7} + \frac{{ - 5}}{{14}}} \right) - \frac{{18}}{{35}}\\ = \frac{2}{5}.\left( {\frac{{ - 6}}{{14}} + \frac{{ - 5}}{{14}}} \right) - \frac{{18}}{{35}}\\ = \frac{2}{5}.\frac{{ - 11}}{{14}} - \frac{{18}}{{35}} = \frac{{ - 11}}{{35}} - \frac{{18}}{{35}} = \frac{{ -29}}{{35}}\end{array}\)
b) \(\left( {\frac{2}{3} - \frac{5}{{11}} + \frac{1}{4}} \right):\left( {1 + \frac{5}{{12}} - \frac{7}{{11}}} \right)\)
\(\begin{array}{l} = \left( {\frac{{2.11.4}}{{3.11.4}} - \frac{{5.3.4}}{{11.3.4}} + \frac{{1.3.11}}{{4.3.11}}} \right):\left( {\frac{11.12}{11.12} + \frac{{5.11}}{{12.11}} - \frac{{7.12}}{{11.12}}} \right)\\ = \left( {\frac{{88 - 60 + 33}}{{121}}} \right):\left( { \frac{{121+55 - 84}}{{121}}} \right)\\ = \frac{{61}}{{121}}:\frac{{92}}{{121}} = \frac{{61}}{{121}}.\frac{{121}}{{92}}= \frac{{61}}{{92}}\end{array}\)
c) \(\left( {13,6 - 37,8} \right).\left( { - 3,2} \right)\)
\( = \left( { - 24,2} \right).\left( { - 3,2} \right) = 77,44\)
d) \(\left( { - 25,4} \right).\left( {18,5 + 43,6 - 16,8} \right):12,7\)
\(\begin{array}{l} = \left( { - 25,4} \right).\left( {62,1 - 16,8} \right):12,7\\ = \left( { - 25,4} \right).45,3:12,7\\ = \left( { - 25,4} \right):12,7.45,3\\ = (- 2).45,3 = - 90,6\end{array}\)
a: \(=\dfrac{2}{5}\cdot\left(-\dfrac{3}{7}-\dfrac{5}{14}\right)-\dfrac{18}{35}\)
\(=\dfrac{2}{5}\cdot\dfrac{-6-5}{14}-\dfrac{18}{35}\)
\(=\dfrac{2}{5}\cdot\dfrac{-11}{14}-\dfrac{18}{35}=-\dfrac{22}{70}-\dfrac{18}{35}=\dfrac{-58}{70}=-\dfrac{29}{35}\)
b: \(=\dfrac{88-60+33}{132}:\dfrac{132+55-84}{132}\)
\(=\dfrac{61}{132}\cdot\dfrac{132}{103}=\dfrac{61}{103}\)
c: \(=-24.2\cdot\left(-3.2\right)=24.2\cdot3.2=77.44\)
d: \(=\dfrac{-25.4}{12.7}\cdot45.3=-2\cdot45.3=-90.6\)
1. Tính:a) A=1253.24; b) B=\(\frac{1}{49^4}\).77; c) C=\(\frac{27^3+9^5}{81^3+3^{11}}\); d) D=\(\frac{\frac{4}{9}+\frac{28}{15}-\frac{12}{4}}{\frac{5}{9}+\frac{35}{15}-\frac{15}{4}}\)
2. a) Tìm GTNN của A= (2x-3)2-7; b) Tìm GTLN của 3- giá trị tuyệt đối của 3x-2
3. Tìm sốx nguyên để các số sau là số nguyên: a)A= 2+\(\frac{3}{x+1}\);b) B=\(\frac{3x-1}{x-1}\)