này mình có vài câu không làm được, xin lỗi bạn nha

\(b,16x^2-8x+1=\left(4x-1\right)^2\\ c,4x^2+12xy+9y^2=\left(2x+3y\right)^2\\ e,=x^2+2x+1+y^2+2y+1+2\left(x+1\right)\left(y+1\right)\\ =\left(x+1\right)^2+2\left(x+1\right)\left(y+1\right)+\left(y+1\right)^2\\ =\left[\left(x+1\right)+\left(y+1\right)\right]^2=\left(x+y+2\right)^2\\ g,=x^2-2x\left(y+2\right)+\left(x+2\right)^2=\left[x-\left(y+2\right)\right]^2=\left(x-y-2\right)^2\\ h,=\left[x+\left(y+1\right)\right]^2=\left(x+y+1\right)^2\)

a) ( x   +   1 ) 2 .                     b) ( x   –   4 ) 2 .

c) x 2 4 + x + 1 ;                   d) ( 2 x   –   2 y ) 2 .

b:=y^2+2y+1+9x^2-12x+4

=(y+1)^2+(3x-2)^2

a:

SỬa đề: 5y^2

=y^2-10y+25+9x^2+4y^2-12xy

=(y-5)^2+(3x-2y)^2

a) x²+6x+9=x²+2.x.3+3²=(x+3)²

b) x²+x+\(\dfrac{1}{4}\)=x²+2.x.\(\dfrac{1}{2}\)+\(\dfrac{1}{4}\)=(x+\(\dfrac{1}{2}\))²

c) 2xy²+x²y⁴+1=(xy²)²+2.xy²+1=(xy²+1)²

a,(x+3)^2

b,(x+1/2)^2

a) (x+3)²

b) (x+\(\dfrac{1}{2}\))²

c) (xy²+1)²

\(a.\)

\(z^2-6z+5-t^2-4t\)

\(=z^2-6z+9-\left(t^2+4t+4\right)\)

\(=\left(z-3\right)^2-\left(t+2\right)^2\)

\(b.\)

\(4x^2-12x-y^2+2y+1\)

Câu này đề sai sao ấy em !

b, mik nghĩ đề sửa thành: \(4x^2-12x-y^2+2y+8\)

\(=4x^2-12x+9-y^2+2y-1\)

\(=\left(2x\right)^2-2.2.3.x+3^2-\left(y^2-2y+1\right)\)

\(=\left(2x-3\right)^2-\left(y-1\right)^2\)

a) 6xy^3+x^2y^6+9

= (xy^3 + 3)^2

b) x^4-2x^2y+y^2

= (x^2 - y)^2

c) x^6+25-10x^3

= (x^3 - 5)^2

a/ 6xy³+x²y⁶+9

= (xy³+3)² bình phương của 1 tổng;cttq: (A+B)²

b/ x⁴-2x²y+y²

= (x²-y)² bình phương của 1 hiệu; cttq (A-B)²

c/ x⁶+25-10x³

=(x³-5)²

\(2xy^2+x^2y^4+1\)

\(=\left(xy^2\right)^2+2.xy^2+1^2\)

\(=\left(xy^2+1\right)^2\)

làm sai bét