\(\dfrac{x^3+64}{2x^3-8x^2+32x}\\ =\dfrac{\left(x+4\right)\left(x^2-4x+16\right)}{2x\left(x^2-4x+16\right)}\\ =\dfrac{x+4}{2x}\)

\(\dfrac{x^3+64}{2x^3-8x^3+32x}\)

\(=\dfrac{\left(x+4\right)\left(x^2-4x+16\right)}{2x\left(x^2-4x+16\right)}\)

\(=\dfrac{x+4}{2x}\)

Nguyễn Huệ Lam ơi cái câu b bn làm sai r cái đoạn đặt ntu chung là 2 x đầu tiên ấy bn

a)

\(\frac{9-\left(x+5\right)^2}{x^2+4x+4}=\frac{3^2-\left(x+5\right)^2}{x^2+2.x.2+2^2}=\frac{\left(3+x+5\right)\left(3-x-5\right)}{\left(x+2\right)^2}\)

\(=\frac{\left(x+8\right)\left(x-2\right)}{\left(x+2\right)^2}\)

b)

\(\frac{32x-8x^2+2x^3}{x^3+64}=\frac{2x\left(x^2-8x+16\right)}{x^3+4^3}=\frac{2x\left(x^2-2.x.4+4^2\right)}{\left(x+4\right)\left(x^2-4x+16\right)}\)

\(=\frac{2x\left(x-4\right)^2}{\left(x+4\right)\left(x^2-4x+16\right)}\)

khó qua mik mới hc lớp 7 thôi

a) (2x^2 +2xy - xy -y^2 ) / (2x^2 - 2xy - xy +y^2)

= 2x(x+y) - y(x+y)  /  2x(x-y) - y(x-y)

= (2x-y)(x+y)  /  (2x-y)(x-y)

= x+y/x-y

Rút gọn cái sau:

\(\frac{32x+4x^2+2x^3}{x^3+64}\)

\(=\frac{2x\left(x^2+2x+16\right)}{\left(x+4\right)\left(x^2-4x+16\right)}\)

Đề có vẻ sai sai ? 

\(A =\frac{32x - 8x^{2} + 2x^{3}}{x^{3}+ 64}\)\(= \frac{2x(16 - 4x + x^{2})}{(x + 4)(x^{2} - 4x + 16)}= \frac{2x(x^{2} - 4x + 16)}{(x + 4)(x^{2} - 4x + 16)}= \frac{2x}{x + 4}\)

\(A=\dfrac{32x-8x^2+2x^3}{x^3+64}\)

\(=\dfrac{2x\left(16-4x+x^2\right)}{\left(x+4\right)\left(x^2-4x+16\right)}\)

\(=\dfrac{2x\left(x^2-4x+16\right)}{\left(x+4\right)\left(x^2-4x+16\right)}\)

\(=\dfrac{2x}{x+4}\).

a) A=\(\frac{x+1}{6x^3-6x^2}-\frac{x-2}{8x^3-8x}=\frac{x+1}{6x^2\left(x-1\right)}-\frac{x-2}{8x\left(x-1\right)\left(x+1\right)}=\frac{4\left(x+1\right)^2-3x\left(x-2\right)}{24x^2\left(x-1\right)\left(x+1\right)}=\frac{4x^2+8x+4-3x^2+6x}{24x^2\left(x-1\right)\left(x+1\right)}=\frac{x^2+14x+10}{24x^2\left(x-1\right)\left(x+1\right)}\)

(4x - 1)(3 - x) - (2x + 3)(2x - 1) = 0

12x + \(4x^2\)- 3 + x - 4x + 2x - 6x + 3 = 0 

\(4x^2\)+ 5x                                           = 0

4x . 4x + 5x                                           = 0

  16x    + 5x                                           = 0

       21x                                                 = 0

           x                                                 = 0

2x(8x + 3) - (4x - 1)(4x + 1) = 13

16x + 6x   - 16x - 4x + 4x +1 = 13

6x +1                                     = 13

6x                                          = 12

  x                                           = 2