`(x-3/4)(4+3x)+0`

`<=>` \(\left[ \begin{array}{l}x-\dfrac34=0\\3x+4=0\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=\dfrac34\\3x=-4\end{array} \right.\) 

`<=>` \(\left[ \begin{array}{l}x=\dfrac34\\x=-\dfrac43\end{array} \right.\) 

Vậy `x=3/4` hoặc `x=-4/3`

Ta có: \(\left(x-\dfrac{3}{4}\right)\left(3x+4\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{4}{3}\end{matrix}\right.\)

17 x 19 = 323

23 x 27 = 621

98 x 95 = 9310

sai rồi

và hiểu theo nghĩa ngược laị

1800 nha

đúng k nhỉ

\(1+2+3+4+5\times1\times2\times3\times4\times5\)

=\(1+2+3+4+\left(5\times1\times2\times3\times4\times5\right)\)

\(=10+600\)

\(=610\)

ban sai rùi nha

bang 450

2x

2x

2x

1:tính

\(\frac{5}{8}\)x\(\frac{9}{7}\)+\(\frac{5}{8}\)x\(\frac{5}{7}\)

=\(\frac{5}{8}\)x\((\)\(\frac{9}{7}\)+\(\frac{5}{7}\)\()\)

=\(\frac{5}{8}\)x2

=\(\frac{5}{4}\)

# hok tốt #

2, 

Bao ngô nặng :

24 . 4/3 = 32 ( kg )

2 bao nặng :

24 + 32 = 56 ( kg )

đ/s:..............

2,

Bao ngô nặng :

24 . 4/3 = 32 ( kg )

2 bao nặng :

24 + 32 = 56 ( kg )

1 + 2 + 3 + 4 + 5 x 1 x 2 x 3 x 4 x 5 + 764 x 31 = 24294

k mình nha

1/ \(=\lim\limits_{x\rightarrow-\infty}x\left(-\sqrt{\dfrac{16x^2}{x^2}-\dfrac{3x}{x^2}+\dfrac{5}{x^2}}+2-\dfrac{5}{x}\right)=\lim\limits_{x\rightarrow-\infty}x\left(-4+2\right)=-\infty\)

\(=\lim\limits_{x\rightarrow+\infty}x\left(\sqrt{\dfrac{16x^2}{x^2}-\dfrac{3x}{x^2}+\dfrac{5}{x^2}}+2-\dfrac{5}{x}\right)=\lim\limits_{x\rightarrow+\infty}x\left(4+2\right)=+\infty\)

2/ \(S=\dfrac{-\dfrac{1}{3}}{1+\dfrac{1}{3}}=-\dfrac{1}{4}\)

4/ 

5/ 

\(f'\left(x\right)=4\left(2m-1\right)x^3-4x\)

Vì tiếp tuyến vuông góc với \(y=5x-2018\Rightarrow f'\left(x\right)=-\dfrac{1}{5}\)

\(\Rightarrow f'\left(1\right)=-\dfrac{1}{5}\Leftrightarrow4\left(2m-1\right)-4=-\dfrac{1}{5}\Leftrightarrow m=\dfrac{39}{40}\)