Giải thì giải từ hình dưới r đến hình trên giúp t nha, t cảm ơn

3:

a: \(\sqrt{14^2}=14\)

b: \(\sqrt{16^2}=16\)

c: \(\sqrt{169}=13\)

d: \(\sqrt{\left(\dfrac{3}{4}\right)^2}=\dfrac{3}{4}\)

1:

a: \(\sqrt{144}=\sqrt{12^2}=12\)

b: \(\sqrt{\left(-13\right)^2}=\left|-13\right|=13\)

c: \(-\sqrt{\dfrac{16}{81}}=-\sqrt{\left(\dfrac{4}{9}\right)^2}=-\dfrac{4}{9}\)

d: \(\sqrt{36}+\sqrt{225}=6+15=21\)

Bạn cần hết ạ? Bạn tách từng bài ra các CH khác nhau, tất cả cả bài này dài lắm b.

vcl giúp t vớiiii

5:

a: Ngày 1 bán được 45*3/5=27m

b: Ngày 2 bán được 27*1/3=9m

Ngày 3 bán được 27-9=18m

Số mét vải ngày 3 bán được so với ngày 1 là:

18/27=66,66%

Bị lỗi chữ ở trên :))
 

1:

góc bZc+góc aZb=180 độ(kề bù)

=>góc bZc=180-góc aZb=180-71=109 độ

2: góc pOn+góc pOa=180 độ(kề bù)

=>góc pOa=180-47=133 độ

3: góc xBz+góc xBm=180 độ(hai góc kề bù)

=>góc xBz=180-32=148 độ

Part 3: Give the correct form of the verb in brackets. (1,5 m)  

Famous places in Ha Noi (visit) ………are visited………every year.

Lan (move) ……………moved…………….to Ho Chi Minh city with her family last summer.

Those students (walk) ………are walking………..up the mountain to visit the shrine of a Vietnamese hero at present.

If we use much pesticide on vegetables, the vegetables (become)………will become……….poisonous and inedible.

How about (make)…………making………….posters on energy and hanging them around our school?

Would you like (have)………to have………..a drink?

Part 4: Give the correct forms of the words in the brackets to finish the following sentences. (1,0 m)

What have fashion designers done to (modern)…………mordernize………the ao dai?

A computer can gather a lot of (inform)…………information…………for different purposes.

In order to keep our environment (pollute) ………unpolluted……….., we shouldn’t drop litter in public places.

Our teacher is pleased that we solved the problems (effect) …………effectively…………..

Part 5: Choose the words or phrases in brackets that best completes each sentence. (1,0 m)

Jeans have never been out of fashion, and today young generation is still fond (in/ on/ at/ of) ……of…….wearing them.

(A/ An/ The/ Every)………The…….Parkers are nice, so van feels like a member of their family.

You (did/ didn’t do/ had/ hadn’t)……didn't do………your homework last night, did you?

If we (go on/ turn off/ look after/ take away)……go on………throwing garbage, the environment will be contamined.

Dùng Ca(OH)₂ em nha vì khí CO₂ và SO₂ đều tác dụng được với dd Ca(OH)₂

hoặc dùng dd br2 và caoh2

\(a)\left|x+\dfrac{1}{2}\right|=3\\ x+\dfrac{1}{2}=\left\{{}\begin{matrix}3\\-3\end{matrix}\right.\\ x=\left\{{}\begin{matrix}3-\dfrac{1}{2}\\-3-\dfrac{1}{2}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{5}{2}\\-\dfrac{7}{2}\end{matrix}\right.\)

\(b)\left|x-1,5\right|=2\\ x-1,5=\left\{{}\begin{matrix}2\\-2\end{matrix}\right.\\ x=\left\{{}\begin{matrix}2+1,5\\-2+1,5\end{matrix}\right.\\ x=\left\{{}\begin{matrix}3,5\\-0,5\end{matrix}\right.\\ c)\left|x-2,5\right|-\dfrac{3}{4}=0\\ \left|x-2,5\right|=0+\dfrac{3}{4}\\ \left|x-2,5\right|=\dfrac{3}{4}\\ x-2,5=\left\{{}\begin{matrix}\dfrac{3}{4}\\-\dfrac{3}{4}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{3}{4}+2,5\\-\dfrac{3}{4}+2.5\end{matrix}\right.\\ x=\left\{{}\begin{matrix}3,25\\1,75\end{matrix}\right.\)

\(d)\dfrac{1}{2}-\left|\dfrac{5}{4}-2x\right|=\dfrac{1}{3}\\ \left|\dfrac{5}{4}-2x\right|=\dfrac{1}{2}-\dfrac{1}{3}\\ \left|\dfrac{5}{4}-2x\right|=\dfrac{1}{6}\\ \dfrac{5}{4}-2x=\left\{{}\begin{matrix}\dfrac{1}{6}\\-\dfrac{1}{6}\end{matrix}\right.\\ 2x=\left\{{}\begin{matrix}\dfrac{5}{4}-\dfrac{1}{6}\\\dfrac{5}{4}-\left(-\dfrac{1}{6}\right)\end{matrix}\right.\\ 2x=\left\{{}\begin{matrix}\dfrac{13}{12}\\\dfrac{17}{12}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{13}{12}:2\\\dfrac{17}{12}:2\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{13}{24}\\\dfrac{17}{24}\end{matrix}\right.\)

\(e)\left|x-\dfrac{1}{2}\right|=4\\ x-\dfrac{1}{2}=\left\{{}\begin{matrix}4\\-4\end{matrix}\right.\\ x=\left\{{}\begin{matrix}4+\dfrac{1}{2}\\-4+\dfrac{1}{2}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{9}{2}\\-\dfrac{7}{2}\end{matrix}\right.\\ f)\left|x+2,5\right|=3\\ x+2,5=\left\{{}\begin{matrix}3\\-3\end{matrix}\right.\\ x=\left\{{}\begin{matrix}3-2,5\\-3-2,5\end{matrix}\right.\\ x=\left\{{}\begin{matrix}0,5\\-5,5\end{matrix}\right.\)

\(g)\left|x+1,5\right|-\dfrac{1}{4}=0\\ \left|x+1,5\right|=0+\dfrac{1}{4}\\ \left|x+1,5\right|=\dfrac{1}{4}\\ x-1,5=\left\{{}\begin{matrix}\dfrac{1}{4}\\-\dfrac{1}{4}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{1}{4}+1,5\\-\dfrac{1}{4}+1,5\end{matrix}\right.\\ x=\left\{{}\begin{matrix}1,75\\1,25\end{matrix}\right.\)

\(h)\dfrac{1}{5}-\left|\dfrac{1}{4}-3x\right|=\dfrac{1}{6}\\ \left|\dfrac{1}{4}-3x\right|=\dfrac{1}{5}-\dfrac{1}{6}\\ \left|\dfrac{1}{4}-3x\right|=\dfrac{1}{30}\\ \dfrac{1}{4}-3x=\left\{{}\begin{matrix}\dfrac{1}{30}\\-\dfrac{1}{30}\end{matrix}\right.\\ 3x=\left\{{}\begin{matrix}\dfrac{1}{4}-\dfrac{1}{30}\\\dfrac{1}{4}-\left(-\dfrac{1}{30}\right)\end{matrix}\right.\\ 3x=\left\{{}\begin{matrix}\dfrac{13}{60}\\\dfrac{17}{60}\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{13}{60}:3\\\dfrac{17}{60}:3\end{matrix}\right.\\ x=\left\{{}\begin{matrix}\dfrac{13}{180}\\\dfrac{17}{180}\end{matrix}\right.\)

\(a,\left|x\right|+\dfrac{1}{2}=3\\ \Rightarrow\left|x\right|=3-\dfrac{1}{2}\\ \Rightarrow\left|x\right|=\dfrac{5}{2}\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{5}{2}\\x=-\dfrac{5}{2}\end{matrix}\right.\)

\(b,10,23-\left|x\right|=5\\ \Rightarrow\left|x\right|=10,23-5\\ \Rightarrow\left|x\right|=5,23\\ \Rightarrow\left[{}\begin{matrix}x=5,23\\x=-5,23\end{matrix}\right.\)

\(c,2\left|x\right|-\dfrac{1}{4}=\dfrac{2}{3}\\ \Rightarrow2\left|x\right|=\dfrac{2}{3}+\dfrac{1}{4}\\ \Rightarrow2\left|x\right|=\dfrac{11}{12}\\ \Rightarrow\left|x\right|=\dfrac{11}{12}:2\\ \Rightarrow\left|x\right|=\dfrac{11}{24}\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{24}\\x=-\dfrac{11}{24}\end{matrix}\right.\)

\(d,6-3\left|x\right|=\dfrac{3}{4}\\ \Rightarrow3\left|x\right|=6-\dfrac{3}{4}\\ \Rightarrow3\left|x\right|=\dfrac{21}{4}\\ \Rightarrow\left|x\right|=\dfrac{21}{4}:3\\ \Rightarrow\left|x\right|=\dfrac{7}{4}\\ \Rightarrow\left[{}\begin{matrix}x=\dfrac{7}{4}\\x=-\dfrac{7}{4}\end{matrix}\right.\)

\(a)\left|x\right|+\dfrac{1}{2}=3\\ \left|x\right|=3-\dfrac{1}{2}\\ \left|x\right|=\dfrac{5}{2}\\ x=\left\{{}\begin{matrix}\dfrac{5}{2}\\-\dfrac{5}{2}\end{matrix}\right.\\ b)10,23-\left|x\right|=5\\ \left|x\right|=10,23-5\\ \left|x\right|=5,23\\ x=\left\{{}\begin{matrix}5,23\\-5,23\end{matrix}\right.\\ c)2\left|x\right|-\dfrac{1}{4}=\dfrac{2}{3}\\ 2\left|x\right|=\dfrac{2}{3}.\dfrac{1}{4}\\ 2\left|x\right|=\dfrac{11}{12}\\ \left|x\right|=\dfrac{11}{12}:2\\ \left|x\right|=\dfrac{11}{24}\\ x=\left\{{}\begin{matrix}\dfrac{11}{24}\\-\dfrac{11}{24}\end{matrix}\right.\)

\(d)6-3\left|x\right|=\dfrac{3}{4}\\ 3\left|x\right|=6-\dfrac{3}{4}\\ 3\left|x\right|=\dfrac{21}{4}\\ \left|x\right|=\dfrac{7}{4}\\ x=\left\{{}\begin{matrix}\dfrac{7}{4}\\-\dfrac{7}{4}\end{matrix}\right.\)

Hình a:

\(\widehat{zAy}\) và \(\widehat{yAx}\)

Hình b:

\(\widehat{BMA}\) và \(\widehat{AMC}\)

\(\widehat{BAM}\) và \(\widehat{MAC}\)

Hình c:

\(\widehat{pOn}\) và \(\widehat{nOy}\)

\(\widehat{nOy}\) và \(\widehat{yOq}\)

\(\widehat{yOq}\) và \(\widehat{qOm}\)

\(\widehat{qOm}\) và \(\widehat{mOx}\)

\(\widehat{mOx}\) và \(\widehat{xOp}\)

\(\widehat{xOp}\) và \(\widehat{pOn}\)

Bài 4:

a: Thể tích của hình hộp là: \(25\cdot3=75\left(cm^3\right)\)

b: Độ dài cạnh của đáy là \(\sqrt{25}=5\left(cm\right)\)

Diện tích xung quanh là: \(2\left(5+5\right)\cdot3=6\cdot10=60\left(cm^2\right)\)

bài 5:

a: Thể tích bể nước mà bể chứa được tối đa là;

\(40\cdot30\cdot25=30000\left(cm^3\right)=30\left(lít\right)\)

b: Diện tích xung quanh là:

\(2\left(40+30\right)\cdot25=50\cdot70=3500\left(cm^2\right)\)

Diện tích kính dùng làm bể là:

\(3500+2\cdot40\cdot30=5900\left(cm^2\right)\)