\(1,2^3\cdot x^2=1,2^5\Leftrightarrow x^2=\dfrac{1,2^5}{1,2^3}=1,2^2=1,44\)

\(\Leftrightarrow x=1,2\) hoặc \(x=-1,2\)

Vậy x = 1,2 hoặc x = -1,2

(1,2)³.\(x^2\) = (1,2)⁵

         \(x^2\) = (1,2)⁵:(1,2)³

        \(x^2\) = (1,2)²

       \(\left[{}\begin{matrix}x=-1,2\\x=1,2\end{matrix}\right.\)

a) \(2^x=8\)

⇔ \(2^x=2^3\)

⇒ \(x=3\)

b) \(3^x=27\)

⇔ \(3^x=3^3\)

⇒ \(x=3\)

c) \(\left(-\dfrac{1}{2}\right)x=\left(-\dfrac{1}{2}\right)^4\)

⇔ \(x=\left(-\dfrac{1}{2}\right)^4\div\left(-\dfrac{1}{2}\right)\)

⇔ \(x=\left(-\dfrac{1}{2}\right)^3\)

d) \(x\div\left(-\dfrac{3}{4}\right)=\left(-\dfrac{3}{4}\right)^2\)

⇔ \(x=\left(-\dfrac{3}{4}\right)^2\cdot\left(-\dfrac{3}{4}\right)\)

⇔ \(x=\left(-\dfrac{3}{4}\right)^3=-\dfrac{27}{64}\)

d) \(\left(x+1\right)^3=-125\)

⇔ \(\left(x+1\right)^3=\left(-5\right)^3\)

⇔ \(x+1=-5\)

⇔ \(x=-5-1=-6\)

2:

a: (x-1,2)^2=4

=>x-1,2=2 hoặc x-1,2=-2

=>x=3,2(loại) hoặc x=-0,8(loại)

b: (x-1,5)^2=9

=>x-1,5=3 hoặc x-1,5=-3

=>x=-1,5(loại) hoặc x=4,5(loại)

c: (x-2)^3=64

=>(x-2)^3=4^3

=>x-2=4

=>x=6(nhận)

 BÚ

a,x - 1,44 : 1,2 = 5,9

x-1,2=5,9

x=5,9+1,2

x=7,1

b,86,5 - x : 8,6 = 23,7

x:8,6=86,5-23,7

x:8,6=62,8

x=62,8 x 8,6

x=540,08

c,( 25,34 - x ) : 2,8 - 1,2 = 3,7

( 25,34 - x ) : 2,8=3,7+1,2

( 25,34 - x ) : 2,8=4,9

( 25,34 - x ) =4,9 x 2,8

( 25,34 - x ) =13,72

 x = 25,34-13,72

x=11,62

d,x + 75% x - 0,25 x = 22,5

x + 0,75 x-0,25x=22,5

x (1+0,75-0,25)=22,5

x * 1,5 = 22,5

x= 22,5:1,5

x=15

e,( x + 1 ) + ( x + 5 ) + ( x +  9 ) + ... + ( x + 29 ) = 960

(x+x+x+x+x+x+x+x)+(1+5+9+13+17+21+25+29)=960

8*x+120=960

8*x=960-120

8*x=840

x=840:8

x=105

a)

` x - 1,44 : 1,2 = 5,9`

` x - 1,2 = 5,9`

`x = 5,9 + 1,2`

`x = 7,1`

b)

` 86,5 - x : 8,6 = 23,7`

` x : 8,6 = 86,5 - 23,7`

` x : 8,6 =  62,8`

` x = 62,8 xx 8,6`

`x = 540,08`

c)

`( 25,34 - x ) : 2,8 - 1,2 = 3,7`

`( 25,34 - x ) : 2,8 =  3,7 + 1,2`

`( 25,34 - x ) : 2,8 = 4,9`

` 25,34 - x = 4,9 xx 2,8`

` 25,34 -x = 13,72`

` x = 25,34 - 13,72`

`x = 11,62`

e)

` ( x + 1 ) + ( x + 5 ) + ( x +  9 ) + ... + ( x + 29 ) = 960`

Có tất cả số hạng là:

\(\left(29-1\right):4+1=8\left(số\right)\)

Tổng dãy số :

\(\left(29+1\right)\times8:2=120\)

` => ( x + x + x+....+ x) + ( 1 + 5 + 9 +....+ 29) = 960`

` 8x + 120 = 960`

` 8x = 960 - 120`

`8x = 840`

` x = 840 : 8`

`x = 105`

mn ơi giúp mik ik mik cần gấp

a)

\(\begin{array}{l}{(1,2)^3}.x = {(1,2)^5}\\x = {(1,2)^5}:{(1,2)^3}\\x = {(1,2)^2}\\x = 1,44\end{array}\)

Vậy \(x = 1,44\).

b)

\(\begin{array}{l}{\left( {\frac{2}{3}} \right)^7}:x = {\left( {\frac{2}{3}} \right)^6}\\x = {\left( {\frac{2}{3}} \right)^7}:{\left( {\frac{2}{3}} \right)^6}\\x = \frac{2}{3}\end{array}\)

Vậy \(x = \frac{2}{3}\).

0,8 x x = 1,2 x 10

0,8 x x = 12

x = 12 : 0,8

x =15

0,8 x X = 1,2 x 10

0,8 x X = 12

X = 12 : 0,8

x =15