\(x^2-y^2+10x-10y=\left(x-y\right)\left(x+y\right)+10\left(x-y\right)=\left(x-y\right)\left(x+y+10\right)\)

\(x^2+3x+x+3=\left(x+1\right)\left(x+3\right)\)

\(=x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)

\(x^2+x+3x+3=x\left(x+1\right)+3\left(x+1\right)=\left(x+1\right)\left(x+3\right)\)

\(x^2-2xy+y^2+3x-3y-4\)

\(=\left(x-y\right)^2-1+3x-3y-3\)

\(=\left[\left(x-y\right)^2-1^2\right]+\left(3x-3y-3\right)\)

\(=\left[\left(x-y\right)-1\right]\left[\left(x-y\right)+1\right]+3\left(x-y-1\right)\)

\(=\left(x-y-1\right)\left(x-y+1\right)+3\left(x-y-1\right)\)

\(=\left(x-y-1\right)\left[\left(x-y+1\right)+3\right]\)

\(=\left(x-y-1\right)\left(x-y+4\right)\)

x²-x-y²-y=(x²-y²)-(x+y)=(x-y)(x+y)-(x+y)=(x+y)(x-y-1)

x²-xy+x-y=x(x-y)+(x-y)=(x+1)(x-y)

\(x^2-4x-y^2+4=\left(x^2-4x+4\right)-y^2=\left(x-2\right)^2-y^2=\left(x-2-y\right)\left(x-2+y\right)\)

ko pt đc nha bạn

thanks

x¹¹ + x¹⁰ + 1 

= ( x¹¹ - x⁹ + x⁸ - x⁶ + x⁵ - x³ + x² ) + ( x¹⁰ - x⁸ + x⁷ - x⁵ + x⁴ - x² + x ) + ( x⁹ - x⁷ + x⁶ - x⁴ + x³ - x + 1 )

= x² ( x⁹ - x⁷ + x⁶ - x⁴ + x³ - x + 1 ) + x(  ( x⁹ - x⁷ + x⁶ - x⁴ + x³ - x + 1 ) + 1( x⁹ - x⁷ + x⁶ - x⁴ + x³ - x + 1 )

= ( x² + x + 1 ) ( x⁹ - x⁷ + x⁶ - x⁴ + x³ - x + 1 )

Chỗ nào không hiểu thì ib nhé :)

x¹¹+x¹⁰+1

=x¹¹+x¹⁰+x⁹-x⁹-x⁸-x⁷+x⁸+x⁷+x⁶-x⁶-x⁵-x⁴+x⁵+x⁴+x³-x³-x²-x+x²+x+1

=(x¹¹+x¹⁰+x⁹)-(x⁹+x⁸+x⁷)+(x⁸+x⁷+x⁶)-(x⁶+x⁵+x⁴)+(x⁵+x⁴+x³)-(x³+x²+x)+(x²+x+1)

=x⁹(x²+x+1)-x⁷(x²+x+1)+x⁶(x²+x+1)-x⁴(x²+x+1)+x³(x²+x+1)-x(x²+x+1)+(x²+x+1)

=(x²+x+1)(x⁹-x⁷+x⁶-x⁴+x³-x+1)