10x + 2^2.5=10^2
a 10x+2^2.5=10
b 125-5(4+x)=15
c 2^6+(218-x)=73
\(a.\)\(10x+2^2.5=10\)
\(\Leftrightarrow10x+4.5=10\)
\(\Leftrightarrow10x+20=10\)
\(\Leftrightarrow10x=10-20\)
\(\Leftrightarrow10x=-10\)
\(\Leftrightarrow x=-10:10\)
\(\Leftrightarrow x=-1\)
\(b.\)\(125-5\left(4+x\right)=15\)
\(\Leftrightarrow5\left(4+x\right)=125-15\)
\(\Leftrightarrow5\left(4+x\right)=110\)
\(\Leftrightarrow4+x=110:5\)
\(\Leftrightarrow4+x=22\)
\(\Leftrightarrow x=22-4\)
\(\Leftrightarrow x=18\)
\(c.\)\(2^6+\left(218-x\right)=73\)
\(\Leftrightarrow64+\left(218-x\right)=73\)
\(\Leftrightarrow218-x=73-64\)
\(\Leftrightarrow218-x=9\)
\(\Leftrightarrow x=218-9\)
\(\Leftrightarrow x=209\)
a)10x+22.5=10
=>10x+4.5=10
=>10x+20 =10
=>10x =10-20
=>10x =-10
=>x =-10:10
=>x =-1
b)125-5(4+x)=15
=>5(4+x) =125-15
=>5(4+x) =110
=>x+4 =110:5
=>x+4 =22
=>x =22-4
=>x =18
c)26+(218-x)=73
=>218-x =73-64
=>218-x =9
=>x =218-9
=>x =209
2^10x(2^2)^10x...(2^10)^10=2^n
Tìm x, biết:
\(\frac{10^{10}+10^{11}+10^{12}}{13^2+14^2\left(2.3x^{-5}-2^3.3^2\right)}=2.5^2.5\)
P=x^10-10x^9+10x^8-10x^7+10x^6-10x^5+10x^4-10x^3+10x^2-10x+10
tisng P với x+9
x^14 -10x^13+10x^12-10x^11+...+10x^2-10x+10 tại x=9
76-{2.[2.5^2-(31-2.3)]}
6^2.10:{780:[10^3-(2.5^3+35.14)]}
Mn ra đáp án nhanh hộ mình ạ
\(76-\left\{2\cdot\left[2\cdot5^2-\left(31-2\cdot3\right)\right]\right\}\)
\(=76-\left\{2\cdot\left[2\cdot25-\left(31-6\right)\right]\right\}\)
\(=75-\left[2\cdot\left(50-25\right)\right]\)
\(=76-\left(2\cdot25\right)\)
\(=76-50\)
\(=26\)
____________________
\(6^2\cdot10:\left\{780:\left[10^3-\left(2\cdot5^3+35\cdot14\right)\right]\right\}\)
\(=36\cdot10:\left\{780:\left[1000-\left(2\cdot125+490\right)\right]\right\}\)
\(=360:\left\{780:\left[1000-\left(250+490\right)\right]\right\}\)
\(=360:\left[780:\left(1000-740\right)\right]\)
\(=360:\left(780:260\right)\)
\(=360:3\)
\(=120\)
a: =76-{2*[2*25-31+6]}
=76-{2*[50-31+6]}
=76-2*25
=76-50=26
b: \(=360:\left\{\dfrac{780}{1000-2\cdot125-490}\right\}\)
\(=360:\dfrac{780}{260}\)
=360/3=120
D=x^14-10x^13+10x^12-10x^11+.....+10x^2-10x+10 tại x=7
G = x^4 + 10x^3 + 10x^2 + 10x + 10 khi x= -9
\(G=x^4+10x^3+10x^2+10x+10\)
\(=x^4+10\left(x^3+x^2+x+1\right)\)
\(=\left(-9^4\right)+10\left[\left(-9\right)^3+\left(-9\right)^2+-9+1\right]\)
\(=6561+10\cdot-656\)
\(=6561-6560\)
\(=1\)
Thay `x=-9` vào biểu thức G:
`G=(-9)^4+10.(-9)^3+10.(-9)^2+10.(-9)+10`
`=6561-7290+810-90+10`
`=1`
Do \(x=-9\Rightarrow x+9=0\)
Ta có:
\(G=\left(x^4+9x^3\right)+\left(x^3+9x^2\right)+\left(x^2+9x\right)+\left(x+9\right)+1\)
\(=x^3\left(x+9\right)+x^2\left(x+9\right)+x\left(x+9\right)+\left(x+9\right)+1\)
\(=x^3.0+x^2.0+x.0+0+1=1\)
A= x^10-10x^9+10x^8-.....+10x^2-10x+1. Tính giá trị của A tại x=9
x=9
=>x+1=10
\(A=x^{10}-10x^9+10x^8-...+10x^2-10x+1\)
\(=x^{10}-x^9\left(x+1\right)+x^8\left(x+1\right)-...+x^2\left(x+1\right)-x\left(x+1\right)+1\)
\(=x^{10}-x^{10}-x^9+x^8+...+x^3+x^2-x^2-x+1\)
=-x+1
=-9+1=-8