mk làm câu b phần 1 thui tại vì câu a phần 1 và 2 DLT làm đúng rồi

b)33.(17-5)-17.(33-5)

=33.17-33.5-17.33-17.5

=(33.17-17.33)-(33.5-17.5)

=0.(33.5-17.5)

=0

a)\(25\cdot\left(-7\right)\cdot4=25\cdot4\cdot\left(-7\right)\)

=\(\left(-7\right)\cdot100=-700\)

b)\(33\cdot\left(17-5\right)-17\cdot\left(33-5\right)\)

=\(33\cdot12-17\cdot28\)

=\(-80\)

2) \(\frac{3}{4}\)giờ =\(45\)phút

2 45 phút bạn nha

a) 18.17 - 3.6.7

= 18.17-18.7

=18.( 17 - 7 )

= 18 . 10

= 180

b) 54 - 6.( 17 + 9) 

= 6.9 - 6 . 26

= 6.( 9 - 26 ) 

= 6 . ( - 17 ) 

= -102

c) 33.(17 - 5 ) - 17.(33-5)

= 33.17 - 33 .3  - 17.33 -  17 . 5 

= 33.17 + ( -33 ) .3 + ( - 17) .33 + ( -17) .5

= 33.17 + ( - 17) . 33 + 33 . ( - 3) + ( -17 ) .5

= 33. [ 17 + ( -17 ) + ( - 3 )] + (-17) . 5

= 33 . ( - 3 ) + ( -17 ) .5

= -99 + ( - 85)

= -184

a) 18 . 17 - 3 . 6 . 7                   b) 54 - 6 . ( 17 + 9 )                             

= 306      - 126                           = 48  . 26                                            

= 180                                        = 1248

,mk giúp đc từng đó nha

\(\frac{17}{33}.\frac{2}{5}+\frac{3}{5}.\frac{17}{33}-\frac{17}{33}\)

\(=\frac{17}{33}\times\frac{2}{5}+\frac{3}{5}\times\frac{17}{33}-\frac{17}{33}\times1\)

\(=\frac{17}{33}\times\left(\frac{2}{5}+\frac{3}{5}-1\right)\)

\(=\frac{17}{33}\times\left(1-1\right)\)

\(=\frac{17}{33}\times0=\frac{17}{33}\)

 Làm he LÀM đi bạ nó lại  cồn bỏ bỏ

\(a,18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

\(b,54-6.\left(17+9\right)\)

\(=54-6.17+6.9\)

\(=54-102+54\)

\(=\left(54+54\right)-102\)

\(=108-102\)

\(=6\)

\(c,33.\left(17-5\right)-17.\left(33-5\right)\)

\(=33.17-33.5-17.33-17.5\)

\(=\left(33.17-17.33\right)-\left[5\left(33-17\right)\right]\)

\(=0-5.16\)

\(=-80\)

a) \(18.17-3.6.7\)

\(=18.17-18.7\)

\(=18.\left(17-7\right)\)

\(=18.10\)

\(=180\)

b) \(54-6.\left(17+9\right)\)

\(=54-102-54\)

\(=-102\)

c) \(33.\left(17-5\right)-17.\left(33-5\right)\)

\(=561-165-561+85\)

\(=-80\)

a , 18 . 17 - 3 . 6 . 7

= 18 .17 - 18 . 7

= 18 . ( 17 - 7 )

= 18 . 10

= 180

b , 54 - 6 . ( 17 + 9 )

= 54 - 6 . 17 + 6 . 9

= 54 - 102 + 54

= ( 54 - 54 ) - 102

= 0 - 102

= - 102

c , 33 . ( 17 - 5 ) - 17 . ( 33 - 5 )

= 33 . 17 - 33 . 5 - 17 . 33 - 17 .5

= 0 - 5 . 16

= 0 - 80

= - 80

33.(17 – 5) – 17.(33 -5)

= 33. 17 – 33.5 – 17.33 + 17.5

= (33.17 – 33. 17) + ( 17.5 – 33.5)

= 0 + 5.(17- 33)

= 5.(- 16) = -80

\(a.\)

\(\dfrac{27}{13}-\dfrac{106}{111}+-\dfrac{5}{111}=\dfrac{27}{13}-\dfrac{106}{111}-\dfrac{5}{111}=\dfrac{27}{13}-\left(\dfrac{106+6}{111}\right)=\dfrac{27}{13}-1=\dfrac{14}{13}\)

\(b.\)

\(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\dfrac{7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+1=\dfrac{23}{11}\)

\(c.\)

\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+-\dfrac{6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)-\left(\dfrac{25}{31}+\dfrac{6}{31}\right)=1-1=0\)

a) \(\dfrac{27}{13}-\dfrac{106}{111}+\dfrac{-5}{111}=\dfrac{27}{13}+\left(\dfrac{-106}{111}+\dfrac{-5}{111}\right)=\dfrac{27}{13}+-1=\dfrac{14}{13}\) 

b) \(\dfrac{12}{11}-\dfrac{-7}{19}+\dfrac{12}{19}=\dfrac{12}{11}+\left(\dfrac{7}{19}+\dfrac{12}{19}\right)=\dfrac{12}{11}+1=\dfrac{23}{11}\) 

c)\(\dfrac{5}{17}-\dfrac{25}{31}+\dfrac{12}{17}+\dfrac{-6}{31}=\left(\dfrac{5}{17}+\dfrac{12}{17}\right)+\left(\dfrac{-25}{31}+\dfrac{-6}{31}\right)=1+-1=0\)

a) 12 + 13 + 14 - 15 - 16 - 17

= (12 - 15) + (13 - 16) + (14 - 17)

= (-3) + (-3) + (-3) = -9

b) (35 - 17) - (25 - 7 + 22)

= 35 - 17 - 25 + 7 - 22

= (35 - 25) - (17 - 7) - 22

= 10 - 10 - 22 = -22