1. ab ( x - 3 ) - a bình ( x - 3 )
2 . ax + ay + bx + by
3. ax + ay - 2x - 2y
4. 2x - 2y + ax - ay
5. 10ax - 5ay - 2x + y
mình cảm ơn trước ạ
a) x(a+b)+a+b
b) ax+ay+2x+2y
c) x2-2y+xy-2x
d) 10ax-5ay-2x+y
\(=\left(a+b\right)\left(x+1\right)\)
\(b,=a\left(x+y\right)+2\left(x+y\right)=\left(a+2\right)\left(x+y\right)\\ c,=x\left(x+y\right)-2\left(x+y\right)=\left(x-2\right)\left(x+y\right)\\ d,=5a\left(2x-y\right)-\left(2x-y\right)=\left(5a-1\right)\left(2x-y\right)\)
Phân tích các đa thức sau thành nhân tử ( phương pháp nhóm các hạng tử )
1) x - y - a( x - y )
2) a - b + x( a - b )
3) a( x - y ) - x + y
4) x( a - b ) - a + b
5) ax + ay + bx + by
6) ax + ay - bx - by
7) - 2x - 2y + ax + ay
8) x2 - xy - 2x + 2y
9) 10ax - 5ax - 5ay + 2x - y
10) 5x2 y + 5xy2 - a2 x + a2 y
Các bạn giải nhanh cho mình 10 câu này nha. Mình đag cần gấp
1) x - y - a(x - y) = (x - y) - a(x - y) = (1 - x)(x - y)
2) a - b + x(a - b) = (a - b) + x(a - b) = (1 + x)(a - b)
3) a(x - y) - x + y = a(x - y) - (x - y) = (a - 1)(x - y)
4) x(a - b) - a + b = x(a - b) - (a - b) = (x - 1)(a - b)
5) ax + ay + bx + by = a(x + y) + b(x + y) = (a + b)(x + y)
6) ax + ay - bx - by = a(x + y) - b(x + y) = (a - b)(x + y)
7) - 2x - 2y + ax + ay = -2(x + y) + a(x + y) = (a - 2)(x + y)
8) x2 - xy - 2x + 2y = x(x - y) - 2(x - y) = (x - 2)(x - y)
Sorry nha, giờ mình chỉ rảnh làm 8 câu thôi
phân tích cac da thuc sau thanh nhan tu:
a) x^3-2x^2 +2x -13
b) x^2y+xy +x +1
c) ax+by+ay+bx
d) x^2 -(a+b)x +ab
e) x^2y +xy^2 -x-y
f) ax^2 +ay-bx^2-by
bn post nhiều nên mình ghi đáp án thôi nhé phần nào sai đề mình cho qua
b)\(\left(x+1\right)\left(xy+1\right)\)
c)\(\left(a+b\right)\left(x+y\right)\)
d)\(\left(x-a\right)\left(x-b\right)\)
e)\(\left(x+y\right)\left(xy-1\right)\)
f)\(\left(a-b\right)\left(x^2+y\right)\)
ax+ay+bx+by
ax+ay+2x+2y
ax+ay-bx-by
ax+ay-2x-2y
nhanh lên mình cần lắm
\(1,ax+ay+bx+by\)
\(=\left(ax+ay\right)+\left(bx+by\right)\)
\(=a\left(x+y\right)+b\left(x+y\right)\)
\(=\left(x+y\right)\left(a+b\right)\)
\(2,ax+ay+2x+2y\)
\(=\left(ax+ay\right)+\left(2x+2y\right)\)
\(=a\left(x+y\right)+2\left(x+y\right)\)
\(=\left(x+y\right)\left(a+2\right)\)
\(3,ax+ay-bx-by\)
\(=\left(ax+ay\right)-\left(bx+by\right)\)
\(=a\left(x+y\right)-b\left(x+y\right)\)
\(=\left(x+y\right)\left(a-b\right)\)
\(4,ax+ay-2x-2y\)
\(=\left(ax+ay\right)-\left(2x+2y\right)\)
\(=a\left(x+y\right)-2\left(x+y\right)\)
\(=\left(x+y\right)\left(a-2\right)\)
ax + ay + bx + by
= a.(x+y) + b.(x+y)
= (x+y).(a+b)
ax + ay + 2x + 2y
= a.(x+y) + 2.(x+y)
= (x+y).(a+2)
ax + ay - bx - by
= a.(x+y) - b.(x+y)
= (x+y).(a-b)
ax + ay - 2x - 2y
= a.(x+y) - 2.(x+y)
= (x+y).(a-2)
bn nào viết rõ hơn giùm mik đc ko.
(a^2+b^2)(x^2+y^2)=(ax+by)^2
<=> a^2x^2 + a^2y^2 + b^2x^2 + b^2y^2 = a^2x^2 + 2abxy + b^2y^2
<=> a^2y^2 + b^2x^2 = 2abxy
<=> a^2y^2 + b^2x^2 - 2abxy = 0
<=> (ay - bx)^2 = 0
=> ay - bx = 0
=> ay = bx
=> a/x = b/y ( x,y khác 0)
Ta có: \(\left(ax+by\right)^2=\left(a^2+b^2\right)\left(x^2+y^2\right)\)
\(\Leftrightarrow a^2x^2+2abxy+b^2y^2=a^2x^2+a^2y^2+x^2b^2+b^2y^2\)
\(\Leftrightarrow2abxy=a^2y^2+x^2b^2\)
\(\Leftrightarrow\left(ay-xb\right)^2=0\)
\(\Leftrightarrow ay=xb\)
hay \(\dfrac{a}{x}=\dfrac{b}{y}\)
1. Phân tích thành x tử
a, xy+1-x-y
b, ax+ay-3x-3y
c,x3-2x2+2x-4
d,x2+ab+ax+bx
e,16-x2+2xy-y2
f,ax2+ax-bx2-bx-a+b
\(a,xy+1-x-y\)
\(=\left(xy-y\right)+\left(1-x\right)\)
\(=y\left(x-1\right)- \left(x-1\right)\)
\(=\left(x-1\right)\left(y-1\right)\)
\(b,ax+ay-3x-3y\)
\(=a\left(x+y\right)-3\left(x+y\right)\)
\(=\left(x+y\right)\left(a-3\right)\)
\(c,x^3-2x^2+2x-4\)
\(=x^2\left(x-2\right)+2\left(x-2\right)\)
\(=\left(x^2+2\right)\left(x-2\right)\)
\(d,x^2+ab+ax+bx\)
\(=\left(x^2+ax\right)+\left(ab+bx\right)\)
\(=x\left(a+x\right)+b\left(a+x\right)\)
\(=\left(a+x\right)\left(b+x\right)\)
\(e,16-x^2+2xy-y^2\)
\(=4^2-\left(x^2-2xy+y^2\right)\)
\(=4^2-\left(x-y\right)^2\)
\(=\left(4-x+y\right)\left(4+x-y\right)\)
\(f,ax^2+ax-bx^2-bx-a+b\)
\(=\left(ax^2-bx^2\right)+\left(ax-bx\right)-\left(a-b\right)\)
\(=x^2\left(a-b\right)+x\left(a-b\right)-\left(a-b\right)\)
\(=\left(a-b\right)\left(x^2+x-1\right)\)
1. Phân tích thành x tử
a, xy+1-x-y
b, ax+ay-3x-3y
c,x3-2x2+2x-4
d,x2+ab+ax+bx
e,16-x2+2xy-y2
f,ax2+ax-bx2-bx-a+b
Phân tích đa thức thành nhân tử ( nhóm nhiều hạng tử )
a) x3 - 2x2 + 2x - 13
b) ax + by + ay + bx
c) x2y + xy2 - x - y
d) ax2 + ay - bx2 - by
Giải từng bước giúp mình nhé !!! Cảm ơn trc
d) ax2 + ay - bx2 - by
= ( ax2 + ay ) - ( bx2 + by )
= a ( x2 + y ) - b ( x2 + y )
= ( x2 + y )( a - b )
c) x2y + xy2 - x - y
= ( x2y + xy2 ) - ( x + y )
= xy ( x + y ) - ( x+ y )
= ( x + y ) ( xy - 1 )
b) ax + by + ay + bx
= ax + ay + bx + by
= a ( x + y ) + b ( x + y )
= ( x + y ) ( a + b )
1. Phân tích thành x tử
a, xy+1-x-y
b, ax+ay-3x-3y
c,x3-2x2+2x-4
d,x2+ab+ax+bx
e,16-x2+2xy-y2
f,ax2+ax-bx2-bx-a+b
a) \(xy+1-x-y\)
\(=x\left(y-1\right)-\left(y-1\right)\)
\(=\left(y-1\right)\left(x-1\right)\)
b) \(ax+ay-3x-3y\)
\(=a\left(x+y\right)-3\left(x+y\right)\)
\(=\left(x+y\right)\left(a-3\right)\)
c) \(x^3-2x^2+2x-4\)
\(=x^2\left(x-2\right)+2\left(x-2\right)\)
\(=\left(x-2\right)\left(x^2+2\right)\)
d) \(x^2+ab+ax+bx\)
\(=x\left(b+x\right)+a\left(b+x\right)\)
\(=\left(b+x\right)\left(a+x\right)\)
e) \(16-x^2+2xy-y^2\)
\(=16-\left(x^2-2xy+y^2\right)\)
\(=4^2-\left(x-y\right)^2\)
\(=\left(4-x+y\right)\left(4+x-y\right)\)
f) \(ax^2+ax-bx^2-bx-a+b\)
\(=\left(ax^2+ax-a\right)-\left(bx^2+bx-b\right)\)
\(=a\left(x^2+x-1\right)-b\left(x^2+x-1\right)\)
\(=\left(x^2+x-1\right)\left(a-b\right)\)
a) \(xy+1-x-y=\left(xy-x\right)+\left(1-y\right)=x\left(y-1\right)+\left(1-y\right)=x\left(y-1\right)-\left(y-1\right)=\left(x-1\right)\left(y-1\right)\)
b) \(ax+ay-3x-3y=a\left(x+y\right)-3\left(x-y\right)=\left(a-3\right)\left(x+y\right)\)
c) \(x^3-2x^2+2x-4=x^2\left(x-2\right)+2\left(x-2\right)=\left(x^2+2\right)\left(x-2\right)\)
d) \(x^2+ab+ax+bx=\left(x^2+ax\right)+\left(ab+bx\right)=x\left(x+a\right)+b\left(a+x\right)=\left(x+b\right)\left(x+a\right)\)
e) \(16-x^2+2xy-y^2=16-\left(x-y\right)^2=\left(4-x+y\right)\left(4+x-y\right)\)
f) \(ax^2+ax-bx^2-bx-a+b=\left(a-b\right)x^2+\left(a-b\right)x-a+b=\left(a-b\right)\left(x^2+x-1\right)\)