`ab(x-3) -a^2(x-3)`
`=(x-3)(a^2-ab)`
__
`ax+ay+bx+by`
`=a(x+y)+b(x+y)`
`=(x+y)(a+b)`
__
`ax+ay -2x-2y`
`=(ax+ay)-(2x+2y)`
`=a(x+y)-2(x+y)`
`=(x+y)(a-2_`
__
`2x-2y +ax-ay`
`=2(x-y)+a(x-y)`
`=(x-y)(2+a)`
__
`10ax -5ay -2x+y`
`= 5a(2x-y) -(2x-y)`
`=(2x-y)(5a-1)`
1: =(x-3)(ab-a^2)
=a(b-a)(x-3)
2: =a(x+y)+b(x+y)
=(x+y)(a+b)
3: =a(x+y)-2(x+y)
=(x+y)(a-2)
4: =2(x-y)+a(x-y)
=(x-y)(a+2)
5: =5a(2x-y)-(2x-y)
=(2x-y)(5a-1)
1) \(ab\left(x-3\right)-a^2\left(x-3\right)=a\left(x-3\right)\left(b-a\right)\)
2) \(ax+ay+bx+by=\left(a+b\right)\left(x+y\right)\)
3) \(ax+ay-2x-2y=\left(a-2\right)\left(x+y\right)\)
4) \(2x-2y+ax-ay=\left(2+a\right)\left(x-y\right)\)
5) \(10ax-5ay-2x+y=5a\left(2x-y\right)-\left(2x-y\right)=\left(5a-1\right)\left(x-y\right)\)
1. \(ab\left(x-3\right)-a^2\left(x-3\right)\)
⇔ \(a\left(x-3\right)+\left(b-a\right)\)
2. \(ax+ay+bx+by\)
⇔ \(a\left(x+y\right)+b\left(x+y\right)\)
⇔ \(\left(x+y\right)\left(a+b\right)\)
3. \(ax+ay-2x-2y\)
⇔ \(a\left(x+y\right)-2\left(x+y\right)\)
⇔ \(\left(x+y\right)\left(a-2\right)\)
4. \(2x-2y+ax-ay\)
⇔ \(2\left(x-y\right)+a\left(x-y\right)\)
⇔ \(\left(x-y\right)\left(2+a\right)\)
5. \(10ax-5ay-2x+y\)
⇔ \(\left(10ax-2x\right)+\left(-5ay+y\right)\)
⇔ \(2x\left(5a-1\right)+y\left(-5a+1\right)\)
Tự nhiên tới đây quên mất cách giải, thông cảm.