=4090506-\(\dfrac{3}{2023}\)*2021+2020

=4090506-\(\dfrac{6063}{2023}\)+2020

=\(\dfrac{8279174035}{2023}\) tối giản luôn rồi nhé

ok

oki

\(=2022\times\left(1+1+1+1+1+5-7\right)\)

= 2022 x 3

= 6066

2022 + 2022 + 2022 + 2022 + 2022 + 2022 x 5 - 2022 x 7

= 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 1 + 2022 x 5 - 2022 x 7

= 2022 x ( 1 + 1 + 1 + 1 + 1 + 5 - 7 )

= 2022 x 3 

= 6066

chờ tí

6 x 2022/9 + 2022/9 x 4 - 2022/9

=6 x 2022/9 + 2022/9 x 4 - 2022/9x1

=2022/9x(6+4-1)

=2022/9x9=2022

Đáp số là 2021/2022 em nhé

\(\dfrac{2021}{2022}.\dfrac{7}{16}+\dfrac{9}{16}.\dfrac{2021}{2022}=\dfrac{2021}{2022}\left(\dfrac{7}{16}+\dfrac{9}{16}\right)=\dfrac{2021}{2022}.1=\dfrac{2021}{2022}\)

=A*(4/2+1/2-5/2)

=A*(5/2-5/2)=0

`2022 \times 123 \times 12 - 2022 \times 11`

`= 2022 \times (123 \times 12 - 11)`

`= 2022 \times (1476 - 11)`

`= 2022 \times 1465`

`= 2962230`

\(50\%+\dfrac{7}{12}-\dfrac{1}{2}\)

\(=\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}\)

\(=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}\)

\(=\dfrac{7}{12}\)

_______________

\(2022\cdot67+2022\cdot43-2022\cdot10\)

\(=2022\cdot\left(67+43-10\right)\)

\(=2022\cdot100\)

\(=202200\)

_____________________

\(10,3+6,9+8,7+13,1\)

\(=\left(13,1+6,9\right)+\left(10,3+8,7\right)\)

\(=20+19\)

\(=39\)

___________________

\(17,58\times43+57\times17,58\)

\(=17,58\times\left(43+57\right)\)

\(=17,58\times100\)

\(=1758\)

tớ ghi sai nên cập nhật lại câu hỏi, phần 3 các bạn trả lời sớm mà bị sai thì bỏ qua cho tớ nhé

\(50\%+\dfrac{7}{12}-\dfrac{1}{2}=\dfrac{1}{2}+\dfrac{7}{12}-\dfrac{1}{2}=\left(\dfrac{1}{2}-\dfrac{1}{2}\right)+\dfrac{7}{12}=\dfrac{7}{12}\)

\(2022\cdot67+2022\cdot43-2022\cdot10=2022\cdot\left(67+43-10\right)=2022\cdot100=202200\)

\(11,3+6,9+8,7+13,1=\left(11,3+8,7\right)+\left(6,9+13,1\right)=20+20=40\)

\(17,58\cdot43+57\cdot17,58=17,58\cdot\left(43+57\right)=17,58\cdot100=1758\)

\(( 675 , 98 + 888 , 66 + 111 , 34 ) × 0 , 01\)

\(( 675 , 98 + 1000 ) × 0 , 01\)

\( 1675 , 98 × 0 , 01\)

\( 16 , 7598 .\)