Dài wa nên mk chỉ ghi đáp án thui nha

a, x=1

b,x=66

c,x=4

d,x=5/3

e,x=17/25

ghi rõ ra cho mình ý b,d,e được ko

b,x+2=35+1/2x

x-1/2x=35-2

1/2x=33

    x=66

d,6+x=7,1/3+2-x

x+x=7,1/3+2-6

2x=10/3

x=5/3

e,x+5=8,2/5-4x

x+4x=8,2/5-5

5x=17/5

x=17/25

\(6\frac{1}{2}-3\frac{1}{3}=\frac{13}{2}-\frac{10}{3}=\frac{39}{6}-\frac{20}{6}=\frac{19}{6}=3\frac{1}{6}\)

\(2\frac{1}{2}\cdot3\frac{1}{4}=\frac{5}{2}\cdot\frac{13}{4}=\frac{65}{8}=8\frac{1}{8}\)

\(8\frac{2}{5}:4\frac{2}{7}=\frac{42}{5}:\frac{30}{7}=\frac{42}{5}\cdot\frac{7}{30}=\frac{42\cdot7}{5\cdot30}=\frac{7\cdot7}{5\cdot5}=\frac{49}{25}=1\frac{24}{25}\)

thành phân số chứ ko phải = hỗn số

\(3,7\times3,8+8,2\times3,7-0,4\times3,7\times5=3,7\times3,8+8,2\times3,7-3,7\times2=3,7\times\left(3,8+8,2-2\right)=3,7\times10=37\)

=3,7(3,8+8,2-2)

=37

=3,7 ✖(3,8+8,2-0,4✖5)

=3,7 ✖10

=37

13,28x8,2 + 1,328 + 1,328x17
= 13,28x8,2  + 1,328 x 18
= 13,28x8,2 + 13,28x1,8
= 13,28(8,2+1,8)
= 13,28 x 10
= 132,8

Tính nhanh

3,7 x 3,8 + 8,2 x 3,7 - 0,4 x 3,7 x 5

= 3,7 x 3,8 + 8,2 x 3,7 - 3,7 x 2

= 3,7 x (3,8 + 8,2 - 2)

= 3,7 x 10

= 37

3,7 x 3,8 + 8,2 x 3,7 - 0,4 x 3,7 x 5

= 3,7 x 3,8 + 8,2 x 3,7 - 3,7 x 2 

= 3,7 x ( 3,8 + 8,2 - 2 )

= 3,7 x 10 

= 37

3,7 x 3,8 + 8,2 x 3,7 - 0,4 x 3,7 x 5

= 3,7 x 3,8 + 8,2 x 3,7 - 3,7 x 2

= 3,7 x ( 3,8 + 8,2 - 2 )

= 3,7 x 10

= 37

a, 

2 x 4 x 8 x 0,5 x 0,125 x 0,25 x (0,4321 + 0,5679)

= 2 x 4 x 8 : 2 : 8 : 4 x 1

= (2 : 2) x (4 : 4) x (8 : 8) x 1

= 1 x 1 x 1 x 1

= 1

đề nó bị dính nhau quá bn!

d) Ta có: \(32\%-0.25:x=-\dfrac{17}{5}\)

\(\Leftrightarrow0.25:x=\dfrac{8}{25}+\dfrac{17}{5}=\dfrac{93}{25}\)

hay \(x=\dfrac{25}{372}\)

Vậy: \(x=\dfrac{25}{372}\)

e) Ta có: \(\left(x+\dfrac{1}{5}\right)^2+\dfrac{17}{25}=\dfrac{26}{25}\)

\(\Leftrightarrow\left(x+\dfrac{1}{5}\right)^2=\dfrac{9}{25}\)

\(\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{5}=\dfrac{3}{5}\\x+\dfrac{1}{5}=-\dfrac{3}{5}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{2}{5}\\x=-\dfrac{4}{5}\end{matrix}\right.\)

Vậy: \(x\in\left\{\dfrac{2}{5};-\dfrac{4}{5}\right\}\)

f) Ta có: \(-\dfrac{32}{27}-\left(3x-\dfrac{7}{9}\right)^3=-\dfrac{24}{27}\)

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=\dfrac{-8}{27}\)

\(\Leftrightarrow3x-\dfrac{7}{9}=-\dfrac{2}{3}\)

\(\Leftrightarrow3x=\dfrac{1}{9}\)

hay \(x=\dfrac{1}{27}\)

g) Ta có: \(60\%\cdot x+0.4x+x:3=2\)

\(\Leftrightarrow\dfrac{4}{3}x=2\)

hay \(x=\dfrac{3}{2}\)

Vậy: \(x=\dfrac{3}{2}\)

h) PT \(\Leftrightarrow\left|\dfrac{20}{9}-x\right|=\dfrac{2}{9}\) \(\Rightarrow\left[{}\begin{matrix}\dfrac{20}{9}-x=\dfrac{2}{9}\\x-\dfrac{20}{9}=\dfrac{2}{9}\end{matrix}\right.\) \(\Leftrightarrow\left[{}\begin{matrix}x=2\\x=\dfrac{22}{9}\end{matrix}\right.\)

  Vậy ...

i) PT \(\Leftrightarrow\dfrac{8}{5}+\dfrac{2}{5}x=\dfrac{16}{5}\) \(\Leftrightarrow\dfrac{2}{5}x=\dfrac{8}{5}\) \(\Leftrightarrow x=4\)

  Vậy ...