\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)

= \(\frac{7}{5}-\frac{4}{5}:\frac{3}{7}\)

= \(\frac{7}{5}-\frac{28}{15}\)

= \(-\frac{7}{15}\)

\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{3}{7}\)

=>\(\frac{28}{15}\cdot\frac{3}{4}-\left(\frac{55}{100}+\frac{25}{100}\right)\cdot\frac{7}{3}\)

=>\(\frac{84}{60}-\frac{80}{100}\cdot\frac{7}{3}\)

=>\(\frac{7}{5}-\frac{4}{5}\cdot\frac{7}{3}=\frac{7}{5}-\frac{28}{15}\)

=>\(\frac{7}{5}-\frac{18}{14}=\frac{98}{60}-\frac{90}{60}=\frac{8}{60}=\frac{4}{30}\)

nhầm , từ cái đoạn \(\frac{7}{5}-\frac{28}{15}=\frac{21}{15}-\frac{18}{15}=\frac{-7}{15}\)

chúc bn học tốt

k nha thankssssssssssssssssssssssssssssssss

\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right):\frac{7}{3}\)

\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{11}{20}+\frac{1}{4}\right):\frac{7}{3}\)

\(=\frac{7}{5}-\frac{4}{5}.\frac{3}{7}\)

\(=\frac{7}{5}-\frac{12}{35}\)

\(=\frac{37}{35}\)

Đặt A=\(1\frac{13}{15}\). \(0,75\) - (\(\frac{11}{20}\)+25%):\(\frac{7}{3}\)

A=\(\frac{28}{15}\). \(\frac{3}{4}\)-(\(\frac{11}{20}\)+\(\frac{1}{4}\)). \(\frac{3}{7}\)

A=\(\frac{7}{5}\)- \(\frac{4}{5}\).\(\frac{3}{7}\)

A=\(\frac{7}{5}\)-\(\frac{12}{35}\)

A=\(\frac{37}{35}\)

\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)

\(=\frac{28}{15}.\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)

\(=\frac{7}{5}-\frac{4}{7}\)

\(=\frac{29}{35}\)

\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)

\(=\frac{28}{15}\cdot\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)

\(=\frac{7}{5}-\frac{4}{7}\)

\(=\frac{29}{35}\)

\(\frac{29}{35}\)

A=3/4

B=29/35

mình nghĩ thế

Sai thôi nhé!

\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)

\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)

\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)

\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)

\(A=1+\frac{1}{2}\)

\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)

\(A=\frac{3}{2}\)

\(1\dfrac{13}{15}\cdot0,75-\left[\dfrac{11}{20}+25\%\right]\div\dfrac{7}{5}\\ =\dfrac{28}{15}\cdot0,75-\dfrac{4}{5}\cdot\dfrac{5}{7}\\ =\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{29}{35}\)

= 28/15 . 3/4 - ( 11/20 + 1/4 ) : 7/3

= 28/15 . 3/4 - 4/5 : 7/3

= 7/5 - 12/35

= 37/35

= \(\dfrac{28}{15}\) . \(\dfrac{3}{4}\) - (\(\dfrac{11}{20}\) + \(\dfrac{1}{4}\)) : \(\dfrac{7}{3}\)

= \(\dfrac{7}{5}\) - (\(\dfrac{11}{20}\) + \(\dfrac{5}{20}\)) : \(\dfrac{7}{3}\)

=  \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) : \(\dfrac{7}{3}\)

=  \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) x \(\dfrac{3}{7}\)

=  \(\dfrac{7}{5}\) - \(\dfrac{12}{35}\)

=  \(\dfrac{49}{35}\) - \(\dfrac{12}{35}\)

= \(\dfrac{37}{35}\)

 = 4/9 : -8 - (-1/4 + 9/20) : 14/5
= 4/9 : -8 - 1/5 : 14/5
= -1/18 - 1/5 : 14/5
= -1/18 - 1/14
= -8/63

a:\(=5-\dfrac{7}{39}\cdot\dfrac{13}{7}+\dfrac{2}{9}=5-1+\dfrac{2}{9}=4+\dfrac{2}{9}=\dfrac{38}{9}\)

b: \(=\dfrac{28}{15}:\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right)\cdot\dfrac{3}{7}\)

\(=\dfrac{112}{45}-\dfrac{4}{5}\cdot\dfrac{3}{7}\)

\(=\dfrac{112}{45}-\dfrac{12}{35}=\dfrac{676}{315}\)